Java中基于月份的日期选择器

Question

有没有比我做的更好的方法来编码它？因为我需要将date解析为string和than解析为int来比较，而且代码相当长。

@Test(priority=3)
 public void test3DateCheck() throws Exception
 {

  String dateOnWebpage = driver.findElement(By.xpath("//div[@id='homeCalendarSection']/div/div[2]/table/tbody/tr/td/div/ul/li")).getText();

  System.out.println("Today Date on webpage is : " + dateOnWebpage);

  //DateFormat dateFormat1 = new SimpleDateFormat("M/dd/yyyy");
  DateFormat dateFormat1 = new SimpleDateFormat("MM");
  Date date = new Date();
  String javaDate1 = dateFormat1.format(date);
  int javaDateSelector = Integer.parseInt(javaDate1);

  if(javaDateSelector < 10)
  { 
      DateFormat dateFormat2 = new SimpleDateFormat("M/dd/yyyy");  
      String javaDate2 = dateFormat2.format(date);
      System.out.println("Today Date from Java is : " + javaDate2);
      Assert.assertEquals(dateOnWebpage, "Today " + javaDate2);
  }
  else
  {
      DateFormat dateFormat3 = new SimpleDateFormat("MM/dd/yyyy");  
      String javaDate3 = dateFormat3.format(date);
      System.out.println("Today Date from Java is : " + javaDate3);
      Assert.assertEquals(dateOnWebpage, "Today " + javaDate3);
  }

}

Answer 1

如果您不关心web页面上的日期是否以月和月中某一天的前导零书写，只想测试日期是否正确：

    DateTimeFormatter dateFormatter = DateTimeFormatter.ofPattern("'Today' M/d/uuuu");
    LocalDate today = LocalDate.now(ZoneId.of("Pacific/Norfolk"));
    System.out.println("Today is " + today);
    LocalDate observedDate = LocalDate.parse(dateOnWebpage, dateFormatter);
    Assert.assertEquals(today, observedDate);

我不是测试字符串，而是解析日期并测试它。即使该模式中有一个M和一个D，解析两位数的月份和两位数的月份日也没有问题。

另一方面，如果您还想测试web页面上的日期是否没有任何前导零，那么最好测试字符串，就像您已经做的那样：

    DateTimeFormatter dateFormatter = DateTimeFormatter.ofPattern("M/d/uuuu");
    LocalDate today = LocalDate.now(ZoneId.of("Pacific/Norfolk"));
    String todayString = today.format(dateFormatter);
    System.out.println("Today is " + todayString);
    Assert.assertEquals("Today " + todayString, dateOnWebpage);