如果在弹出窗口外单击，请关闭弹出窗口

Question

我有这段代码显示了一个按钮谁显示一个弹出窗口，我希望用户能够关闭弹出窗口点击它的外部时，它是打开的。

    /* Clean up the URL from '#popup1' in the end */
    history.replaceState(null, null, ' ');
    

    /* Take off the popup from DOM before clicking in case user refresh*/
    let id_popup = document.querySelector('#popup1');
    let popup = id_popup.parentNode
    popup.removeChild(id_popup);

    

    /*Opening the popup*/
    function Open() {
      popup.appendChild(id_popup);
      
      let class_popup = document.querySelector('.popup');
      window.addEventListener('click', function (e) {

        if (!class_popup.contains(e.target)) {
          alert('You\'re clicking outside the popup !') 
        }
      });
    }


    /*Closing the popup*/
    function Close() {
      popup.removeChild(id_popup);
      history.replaceState(null, null, ' ');
    }

css prettyprint-override">  .button {
    font-size: 1em;
    padding: 10px;
    color: #000;
    border: 2px solid #06D85F;
    border-radius: 20px/50px;
    text-decoration: none;
    cursor: pointer;
    transition: all 0.3s ease-out;
  }

  .button:hover {
    background: #06D85F;
  }

  .overlay {
    position: fixed;
    top: 0;
    bottom: 0;
    left: 0;
    right: 0;
    background: rgba(0, 0, 0, 0.7);
    transition: opacity 500ms;
    visibility: hidden;
    opacity: 0;
  }

  .overlay:target {
    visibility: visible;
    opacity: 1;
  }

  .popup {
    margin: 70px auto;
    padding: 20px;
    background: #fff;
    border-radius: 5px;
    width: 60%;
    position: relative;
    transition: all 5s ease-in-out;
  }

  .popup h2 {
    margin-top: 0;
    color: #333;
    font-family: Tahoma, Arial, sans-serif;
  }

  .popup .close {
    position: absolute;
    top: 20px;
    right: 30px;
    transition: all 200ms;
    font-size: 30px;
    font-weight: bold;
    text-decoration: none;
    color: #333;
  }

  .popup .close:hover {
    color: #06D85F;
  }

  .popup .content {
    max-height: 30%;
    overflow: auto;
  }

  @media screen and (max-width: 700px) {
    .box {
      width: 70%;
    }

    .popup {
      width: 70%;
    }
  }

<a class="button" href="#popup1" onclick="Open()">Let me Pop up</a>

</div>
<title>hi</title>
<div id="popup1" class="overlay">
  <div class="popup">
    <h2>Title</h2>
    <a class="close" onclick="Close()" href="javascript://">&times;</a>
    <div class="content">
      Text

    </div>
  </div>

Answer 1

尝试以下操作：

let allElems = document.querySelectorAll("body > div:not(#popup1)"); // Special query selector to get everything except .popup and its children

Array.from(allElems).forEach(elem => // Convert to iterable (with Array.from) and loop through all elements selected
  elem.addEventListener('click', function (e) { // Give them all the click event listener.
    alert('You\'re clicking outside the popup !') 
  });
}

问题主要出在if语句上，因为.contains有点搞砸了事情。另一种方法是将两个元素都转换为字符串，并以这种方式比较它们，但这种方法更好，也更快（稍微），因为我们不需要检查每一次单击是否在框中。