我如何用连字符（“-”）测试信用号码，使其无效。当我尝试4003-6000-0000-0014时，我遇到了错误

Question

我无法获得包含处女膜的信用卡号码，因为INVALID，例如4003-6000-0000-0014必须给我INVALID，但它给我字符串错误。

公共类程序 {

public static void main(String[] args) 
{
    Scanner userInput = new Scanner(System.in) ;
    

    System.out.println("How many credit card you want to check?");
    int numOfCredit = userInput.nextInt() ;
    
    int creditnumbers[] = new int[numOfCredit] ;
    
    for (int i = 0 ; i<numOfCredit ; i++)
    {
        System.out.println("Enter credit card number "+(i+1)+": ") ;
        String creditNumber = userInput.next() ;
        
        validateCreditCardNumber(creditNumber);
        
        
    }
}


private static void validateCreditCardNumber(String str) { // function to check credit numbers

    int[] ints = new int[str.length()];
    for (int i = 0; i < str.length(); i++) {
        ints[i] = Integer.parseInt(str.substring(i, i + 1));
    }
    for (int i = ints.length - 2; i >= 0; i = i - 2) {
        int j = ints[i];
        j = j * 2;
        if (j > 9) {
            j = j % 10 + 1;
        }
        ints[i] = j;
    }
    
    
    int sum = 0;
    for (int i = 0; i < ints.length; i++) 
    {
        sum += ints[i];
    }
    if (sum % 10 == 0) 
    {
        System.out.println("VALID");
    } 
    
    else 
    {
        System.out.println("INVALID");
    }
}

}

我用处女膜跑步后出现以下错误：

线程“main”java.lang.NumberFormatException中出现异常：对于输入字符串“-”，位于java.base/java.lang_NumberFormationException.forInputString（NumberFormatExcemption.java:68），位于java.gase/java.lag.Integer.parseInt（Integer.java:642），位于testing/testing.prog.validateCreditCardNumber（prog.java:33），位于测试/测试.prog.main（prog.java：22）

Answer 1

可以将字符串“-”替换为“”（空白），然后应用此函数：

    String card = "4003-6000-0000-0014";

    Boolean t = check(card.replace("-",""));

    public static boolean check(String ccNumber)
    {
        int sum = 0;
        boolean alternate = false;
        for (int i = ccNumber.length() - 1; i >= 0; i--)
        {
            int n = Integer.parseInt(ccNumber.substring(i, i + 1));
            if (alternate)
            {
                n *= 2;
                if (n > 9)
                {
                    n = (n % 10) + 1;
                }
            }
            sum += n;
            alternate = !alternate;
        }
        return (sum % 10 == 0);
    }