Hibernate一对一映射注释插入异常（插入跨国表时，主表数据不应更改）

Question

CREATE TABLE M_SERVICE
(
   SERVICE_ID    NUMBER (10) PRIMARY KEY,
   SERVICE_NM    VARCHAR2 (255),
   ACTIVE_SW     CHAR (1),
   LST_UPDT_DT   DATE,
   LST_UPDT_BY   VARCHAR2 (32)
)

CREATE TABLE T_JOB
(
   JOB_ID          NUMBER PRIMARY KEY,
   JOB_NM          VARCHAR2 (32),
   JOB_DESC        VARCHAR2 (2000),
   SERVICE_ID      NUMBER,
   DUE_DT          DATE,
   LST_UPDT_DT     DATE,
   LST_UPDT_BY     VARCHAR2 (32),
   CONSTRAINT T_JOB_FK1 FOREIGN KEY
      (SERVICE_ID)
       REFERENCES M_SERVICE (SERVICE_ID)
)

@Entity
@Table(name = "M_SERVICE")
public class ServiceVO implements Serializable {
    private static final long serialVersionUID = -2684205897352720653L;
    @Id
    @GeneratedValue(strategy = GenerationType.AUTO, generator = "SEQ_SERVICE_ID")
    @SequenceGenerator(name = "SEQ_SERVICE_ID", sequenceName = "SEQ_SERVICE_ID")
    @Column(name = "SERVICE_ID")
    private Integer serviceId;

    @Column(name = "SERVICE_NM")
    private String serviceName;

    @Column(name = "ACTIVE_SW")
    private char activeSwitch;  

    @Column(name = "LST_UPDT_DT")
    @Temporal(TemporalType.DATE)
    private Date lastUpdatedDt;

    @Column(name = "LST_UPDT_BY")
    private String lastUpdatedBy;
 //Getter & Setters.
}

@Entity
@Table(name = "T_JOB")
public class JobVO implements Serializable {
    private static final long serialVersionUID = 7167763557817486917L;

    @Id
    @GeneratedValue(strategy = GenerationType.AUTO, generator = "SEQ_JOB_ID")
    @SequenceGenerator(name = "SEQ_JOB_ID", sequenceName = "SEQ_JOB_ID")
    @Column(name = "JOB_ID")
    private Integer jobId;

    @Column(name = "JOB_NM", nullable = false)
    private String jobName;

    @Column(name = "JOB_DESC")
    private String jobDesc;

    @OneToOne(cascade = CascadeType.ALL)
    @JoinColumn(name = "SERVICE_ID", referencedColumnName = "SERVICE_ID", insertable = false, updatable = false)
    private ServiceVO service;

    @Column(name = "DUE_DT", nullable = false)
    @Temporal(TemporalType.DATE)
    private Date dueDate;

    @Column(name = "LST_UPDT_DT", nullable = false)
    @Temporal(TemporalType.DATE)
    private Date lastUpdatedDt;

    @Column(name = "LST_UPDT_BY", nullable = false)
    private String lastUpdatedBy;
//Getter & Setters.
}

this.sessionFactory.getCurrentSession().get(JobVO.class, id);

JobVO[jobid=1,jobname=job name,jobdesc=desc,service=servicevo[serviceid=2,serviceName=tax Audit,activeSwitch=y,lastupdateddt=2013-08-31,lastupdatedby=mahesh],duedate=2013-09-01,lastupdateddt=2013-09-01,lastupdatedby=mahesh]

但如果我试图插入一个工作手段，

            JobVO jobVO = new JobVO();
        jobVO.setAuditorId(1);                  
        jobVO.setDueDate(new Date());
        jobVO.setJobDesc("VAT1");
        jobVO.setJobName("Account");
        jobVO.setLastUpdatedBy("Mahesh");
        jobVO.setLastUpdatedDt(new Date());
        ServiceVO service=new ServiceVO();
        service.setServiceId(getClientId());
        jobVO.setService(service);
            this.sessionFactory.getCurrentSession().persist(jobVO);

得到如下错误，org.springframework.orm.hibernate4.hibernateOptimisticLockingFailureException：批处理更新从更新[0]html" target="_blank">返回意外的行计数；实际行数：0；预期：1；嵌套异常是org.hibernate.stalestateException：批处理更新从更新[0]返回意外的行计数；实际行数：0；应为：在org.springframework.orm.hibernate4.SessionFactoryUtils.converthibernateAccessException(SessionFactoryUtils.java:181)在org.springframework.orm.hibernate4.HibernateTransactionManager.converthibernateAccessException(HibernateTransactionManager.java:680)

请帮我解决这个问题。

Answer 1

发生错误是因为有2个事务处理同一记录。如果一条记录由两个事务读取，并且该记录首先由一个事务保存，则在第二个事务中抛出乐观锁定异常，因为系统假定没有其他人会修改该记录。

您是否在批处理模式下使用多线程？

有不同的解决方案：

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