如何使用Wiremock在字段中返回请求正文作为响应

Question

我有一个 JSON 请求，如下所示：

{
    "fieldOne": 12345,
    "fieldTwo": 1234,
    "fieldThree": "2019-12-05T12:32:42.323905",
    "fieldFour": "string",
    "fieldFive": 5432,
    "fieldSix": "string",
    "fieldSeven": "string",
    "fieldEight": "string"
}

作为响应，我需要在一个字段中发送完整的请求JSON对象。我的Wiremock存根JSON是，

{
  "request": {
    "method": "POST",
    "urlPath": "/endpoint"
},
  "response": {
    "status": 200,
    "jsonBody": {
      "request": "{{{request.body}}}", //If I remove quotes here then I get error so I added the quotes
      "anotherField": "string"
    },
    "headers": {
      "Content-Type": "application/json;charset=UTF-8"
    },
    "transformers": ["response-template"]
  }
}

如何在响应字段中发送请求正文？

我现在收到错误：

    Illegal unquoted character ((CTRL-CHAR, code 10)): 
has to be escaped using backslash to be included in string value\n at [Source: (

我使用的是导致此问题的wiremock2.19.0版本。我将版本升级到2.21.0，现在问题解决了

但是在响应中，我仍然遇到以下问题，其中请求正文位于双引号内，这是无效的JSON。响应：-

{
    "request": "{ //Here the double quotes should not be present before curly brace
        "fieldOne": 12345,
        "fieldTwo": 1234,
        "fieldThree": "2019-12-05T12:32:42.323905",
        "fieldFour": "string",
        "fieldFive": 5432,
        "fieldSix": "string",
        "fieldSeven": "string",
        "fieldEight": "string"
    }",
    "anotherField": "string"
}




Answer 1

使用body而不是jsonBody。然后可以以任何需要的方式格式化响应消息（正文双引号中的内容）。

这也适用于线膛2.19.0版本

{
  "request": {
    "method": "POST",
    "urlPath": "/endpoint"
},
  "response": {
    "status": 200,
    "body": "{\"request\": {{{request.body}}}, \"anotherField\": \"string\" }",
    "headers": {
      "Content-Type": "application/json;charset=UTF-8"
    },
    "transformers": ["response-template"]
  }
}