保存新记录时的OneToOne CONSTRAINTVIOLION，PK提供

Question

我们有一个名为顾客的实体，它与实体地址有OneToOne关系。

客户的主键应手动定义。应自动定义地址”主键。

因此，在Customer中，我省略了@GeneratedValue并手动提供is值。但是，在尝试保存时，我遇到以下错误：

2018-11-07 10:42:17.810 ERROR 1257 --- [nio-8080-exec-2] o.h.i.ExceptionMapperStandardImpl        : HHH000346: Error during managed flush [Validation failed for classes [br.com.customers.entity.Address] during persist time for groups [javax.validation.groups.Default, ]
List of constraint violations:[
    ConstraintViolationImpl{interpolatedMessage='não pode ser nulo', propertyPath=street, rootBeanClass=class br.com.customers.entity.Address, messageTemplate='{javax.validation.constraints.NotNull.message}'}

问题是正在提供address.street，我不知道为什么JPA抱怨它是空的...

下面是我试图保存的JSON主体。（正在正确反序列化，因为地址不为空）

{
    "customer_Id": 50,
    "name": "name",
    "company_name": "company_name",
    "email": "[e-mail]",
    "business_phone": "[phone]",
    "mobile_phone": "[phone]",
    "document": "123456789",
    "state_registration_number": "ISENTO",
    "state_registration_type": "NO_CONTRIBUTOR",
    "city_registration_number": "ISENTO",
    "classification": "AUTO",
    "address": {
        "street": "STREET NAME",
        "number": "NUMBER",
        "complement": "COMPLEMENT",
        "zip_code": "ZIP_CODE",
        "neighborhood": "NEIGHBORHOOD",
        "city": "CITY",
        "state": "STATE"
    }
}

以下是客户实体：

@Data
@Entity(name = "X_CUSTOMERS")
public class Customer {

    @Id
    private int customer_Id;

    @NotNull
    private String name;

    private String company_name;

    private String email;

    private String business_phone;

    private String mobile_phone;

    @NotNull
    private String document;

    private String state_registration_number;

    private String state_registration_type;

    private String city_registration_number;

    @NotNull
    private String classification;

    @OneToOne(fetch = FetchType.EAGER, cascade = CascadeType.PERSIST)
    @JoinColumn(name = "address_id")
    private Address address;

}

在此，地址实体：

@Data
@Entity(name = "X_ADDRESS")
public class Address {

    @Id
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    private int address_Id;

    @NotNull
    private String street;

    private String number;

    private String complement;

    private String zip_code;

    private String neighborhood;

    private String city;

    private String state;

}

我做错了什么？谢谢

添加代码确实持久化实体：

客户资源库：

public interface CustomerRepository extends JpaRepository<Customer, Integer> {

}

坚持：

@RestController
@RequestMapping("/customers")
public class CustomersController {

    private CustomerRepository customerRepository;

    public CustomersController(CustomerRepository customerRepository) {
        this.customerRepository = customerRepository;
    }

    @PostMapping
    public Customer postCustomer(@RequestBody Customer customer) {
        return customerRepository.save(customer);
    }


}




Answer 1

如果您添加级联类型。合并，就行了

@OneToOne(fetch = FetchType.EAGER, cascade = { CascadeType.PERSIST, CascadeType.MERGE})
    @JoinColumn(name = "address_id")
    private Address address;

您设置了客户id（50），以便执行以下行的SimpleParepository。

return this.em.merge(entity); 

Answer 2

通过阅读Hibernate文档，save操作只保存具有自动生成ID的实体。因此，如果您打算自己设置id，那么您需要的是更改persist的insert方法。由于您的客户的id不是自动生成的，所以这可能就是问题所在。你可以在这个博客上读到更多。

@PostMapping
public Customer postCustomer(@RequestBody Customer customer) {
    return customerRepository.persist(customer);
}

希望有帮助。