HTML5套接字与Python

Question

试着找出我做错了什么。我一直收到这样的错误：“失败：WebSocket握手期间出错：Sec WebSocket接受不匹配”。

下面是我从服务器得到的：

GET /?encoding=text HTTP/1.1
Upgrade: websocket
Connection: Upgrade
Host: localhost:8026
Origin: http://www.websocket.org
Pragma: no-cache
Cache-Control: no-cache
Sec-WebSocket-Key: en04jzbfLcwcFhk5qnUxJg==
Sec-WebSocket-Version: 13
Sec-WebSocket-Extensions: x-webkit-deflate-frame
User-Agent: Mozilla/5.0 (Macintosh; Intel Mac OS X 10_7_4) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/27.0.1453.93 Safari/537.36

我采用了“EN04JZBFLCFCHK5QNUXJG==”并添加了“258EAFA5-E914-47DA-95CA-C5AB0DC85B11”以获得以下内容：

en04jzbfLcwcFhk5qnUxJg==258EAFA5-E914-47DA-95CA-C5AB0DC85B11

所以我的回应是：

HTTP/1.1 101 Switching Protocols
Upgrade: websocket
Connection: Upgrade
Sec-WebSocket-Accept: MmJjMDQ2NTc0ZDE3MWVhNjA2ZmE0ZGNhYzQzYjliZmZkNzFmZDk1MQ==

我不确定我做错了什么，但从我在其他示例中看到的情况来看，我的websocket accept键似乎相当长。

下面是我的代码，任何想法都会有帮助。

#!/usr/bin/env python

import socket
import thread
import hashlib
import base64
import binascii

def handshake(conn):
    request = conn.recv(1024).strip()
    print request

    specificationGUID = "258EAFA5-E914-47DA-95CA-C5AB0DC85B11"
    websocketKey = ''

    lines = request.splitlines()
    for line in lines:
            args = line.partition(": ")
            if args[0] == 'Sec-WebSocket-Key':
                    websocketKey = args[2]
    print websocketKey

    fullKey = hashlib.sha1(websocketKey + specificationGUID).hexdigest()
    acceptKey = base64.b64encode(fullKey)

    response = 'HTTP/1.1 101 Switching Protocols\r\nUpgrade: websocket\r\nConnection: Upgrade\r\nSec-WebSocket-Accept: ' + acceptKey + '\r\n\r\n'
    conn.send(response)
    print response

def accept(conn):
    def threaded():
        while True:
            handshake(conn)

thread.start_new_thread(threaded, ())

if __name__ == "__main__":
    HOST, PORT = 'localhost', 8026
    server = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
    server.bind((HOST, PORT))
    server.listen(5)

    print "Listening on %s" % ("%s:%s" % server.getsockname())

    while 1:
            conn, addr = server.accept()
            accept(conn)

Answer 1

我发现了问题，我用了。hexdigest（）而不仅仅是使用。摘要（）。更改后，连接成功。