JQuery-如果id相同，只显示一个id并在周[duplicate]时添加它

Question

我有以下示例数据：

[{"id":"2", "weeks":2}, {"id":"2", "weeks":4}, {"id":3, "weeks":7}]

我想我将只显示一个，如果id是多余的，但添加所有的星期，该id有

我的尝试：

var data = [{"id":"2", "weeks":2}, {"id":"2", "weeks":4}, {"id":3, "weeks":7}];
var weeks = 0;
for (var i=0; i<data.length; i++){
    weeks += data[i].weeks;
}

所需输出

[{"id":"2", "weeks":6}, {"id":3, "weeks":7}]

Answer 1

您可以将数组#reduce()与object.values()一起使用。根据ID对数据进行分组，并在对象中添加用于重复ID的周。使用object.values()从对象中获取值。

const data = [{"id":"2", "weeks":2}, {"id":"2", "weeks":4}, {"id":3, "weeks":7}],
      result = Object.values(data.reduce((r,{id,weeks}) => {
        r[id] = r[id] || {id, weeks : 0};
        r[id].weeks += weeks;
        return r;
      },{}));
console.log(result);