二进制到十进制计算器InputMismatchException

Question

public class Main {

    public static void main(String[] args) {
        Scanner scan = new Scanner(System.in);
        System.out.println("Please enter a binary number to convert to decimal: ");
        long binaryNum = scan.nextLong();
        System.out.println(binaryConverter(binaryNum));
        scan.close();

}

    public static long binaryConverter(long binaryNum) {
        String binaryString = Long.toString(binaryNum);
        long decimalValue = 0;
        for(int i = 0; i < binaryString.length(); i++) {
            if((binaryNum%10) == 0) {
                binaryNum = binaryNum/10;
            } else if((binaryNum%10) == 1) {
                decimalValue += Math.pow(2, i);
                binaryNum = binaryNum/10;
            } else {
                System.out.println("This isn't a binary number. Please try again.");
                break;
            }
        }   
        return decimalValue;
}
}

Answer 1

使用Scanner.NextLong(2)，其中2是基数。那么您将读取一个实际的二进制数。

long number = scanner.nextLong(2);
System.out.println(number);

生产

144115188075855871

供输入

111111111111111111111111111111111111111111111111111111111