选择

Question

我在xaml中创建了一个树景。

<TreeView Name="exportTreeView" ItemsSource="{Binding}" Width="350" >
<TreeView.Resources>
    <DataTemplate x:Key="layersTemplate">
        <StackPanel Orientation="Horizontal" Margin="10,0,0,0">
            <CheckBox Foreground="White" IsChecked="{Binding IsToBeExported}" VerticalAlignment="Center" />
            <Label Style="{StaticResource baseStyle}" Content="{Binding Path=Name}" VerticalAlignment="Center" />
        </StackPanel>
    </DataTemplate>
    <HierarchicalDataTemplate x:Key="objectTemplate" ItemsSource="{Binding Path=LayersList}" ItemTemplate="{StaticResource ResourceKey=layersTemplate}">
        <StackPanel Orientation="Horizontal" Height="15" Margin="10,0,0,0">
            <CheckBox Foreground="White" IsChecked="{Binding IsToBeExported}" VerticalAlignment="Center" />
            <Label Style="{StaticResource baseStyle}" Content="{Binding Path=Name}" VerticalAlignment="Center" />
        </StackPanel>
    </HierarchicalDataTemplate>
</TreeView.Resources>
<TreeView.ItemTemplate>
    <HierarchicalDataTemplate ItemsSource="{Binding Path=ObjectList}" ItemTemplate="{StaticResource ResourceKey=objectTemplate}">
        <StackPanel Orientation="Horizontal" Margin="10,0,0,0">
            <CheckBox Foreground="White" IsChecked="{Binding IsToBeExported}" VerticalAlignment="Center" />
            <Label Style="{StaticResource baseStyle}" Content="{Binding Path=Name}" VerticalAlignment="Center" />
        </StackPanel>
    </HierarchicalDataTemplate>
</TreeView.ItemTemplate>

树结构如下图所示。每个家长可以有任意数量的孩子

Parent
  -Child
    --Grandchild

我有所有级别的复选框。我不知道如何单独访问它的节点，也不知道如何使用树数据。

在我的VM类中，我将TreeView的datacontext设置为3类列表，如下所示：

public class MProject
{
    public string Name { get; set; }
    public bool IsToBeExported { get; set; }
    public List<MWorkObject> ObjectList { get; set; }
}

public class MWorkObject
{
    public string Name { get; set; }
    public bool IsToBeExported { get; set; }
    public List<MLayer> LayersList { get; set; }
}

public class MLayer
{
    public string Name { get; set; }
    public bool IsToBeExported { get; set; }
}

我的要求是：

1. 选择父项应选择其所有子项和孙子项
2. 如何在代码中标识所选的项目？需要它做进一步的处理

请帮忙。

Answer 1

您需要为类实现INotifyPropertyChanged。然后

1. 在MProject中导出IsToBeExported的setter中处理所有子项（将IsToBeExported设置为您需要的内容）。绑定使更改在树中可见

例子：

public class ViewBase :INotifyPropertyChanged
{
    public event PropertyChangedEventHandler PropertyChanged;

    protected void NotifyPropertyChanged(string info)
    {       
        PropertyChanged?.Invoke(this, new PropertyChangedEventArgs(info));
    }
}

public class MProject : ViewBase
{
    public string Name
    {
        get
        {
            return _name;
        }
        set
        {
            if (value != _name)
            {
                _name = value;
                NotifyPropertyChanged(nameof(Name));
            }
        }
    }
    private string _name;

    ...
}