尝试创建双精度变量类型的数组时出错

Question

我正在尝试创建一个程序，它从用户那里获取两倍的值，并将它们存储在数组中，然后再对它们进行分割和四舍五入。然而，我在尝试创建双数组时不断收到错误消息。

 double n = sc.nextDouble();

    double a[] = new double[n];
    double b[] = new double[n];
    double roundedValues[] = new double[n];

    for (double i = 0; i < a.length; i++) {
        System.out.println("Please enter the values you would like to divide as pairs of two numbers: ");
        // Read pair and store it inside i-th position of a and b arrays 
        System.out.println("Enter first number: ");
        a[i] = sc.nextDouble();
        System.out.println("Enter second number you would like to divide by: ");
        b[i] = sc.nextDouble();
        roundedValues[i] = Math.round(a[i] / b[i]);
    }

我在声明数组时得到的错误是：

不兼容类型：从双精度到整数的有损转换

Answer 1

a[i] and b[i] expect int type, but you supply double to it
Should be 
 for (int i = 0; i < a.length; i++) {

和

 double n = sc.nextDouble();
   should be changed to:
 int n = sc.nextInt();

Answer 2

首先是变量< code>n，定义为< code > double n = sc . next double()；是一个双精度值。你不能创建一个长度为double的数组，因为这样你可能会得到半个元素。想象一个4.5元素长的数组！

定义n

int n = sc.nextInt（）
或
int n = （int）sc.next双（）;

其次，< code>i也是双精度的！这样定义它:

<代码>用于（int i=0；i

这样编译器就知道i是一个整数，不必担心需要在双index处检索元素，就像第4.2个元素一样！（它不存在，也不应该存在）

这是固定的代码：
int n = sc.nextInt（）;

double a[] = new double[n];
double b[] = new double[n];
double roundedValues[] = new double[n];

for (int i = 0; i < a.length; i++) {
    System.out.println("Please enter the values you would like to divide as pairs of two numbers: ");
    // Read pair and store it inside i-th position of a and b arrays 
    System.out.println("Enter first number: ");
    a[i] = sc.nextDouble();
    System.out.println("Enter second number you would like to divide by: ");
    b[i] = sc.nextDouble();
    roundedValues[i] = Math.round(a[i] / b[i]);
}