Spring3不工作@valid当json请求时我得到了400个错误请求

Question

@RequestMapping(consumes = MediaType.ALL_VALUE, produces = MediaType.ALL_VALUE,value =
    "doAdd", method = RequestMethod.POST)
@ResponseBody
public Customer doAdd(@RequestBody @Valid Customer inData){
    this.customerService.addData(inData);
    return inData;
}

和错误处理方法为：

@ExceptionHandler
@ResponseStatus(value = HttpStatus.BAD_REQUEST)
@ResponseBody
public void ajaxValidationErrorHandle(MethodArgumentNotValidException errors ,
    HttpServletResponse response) throws BusinessException {
    List<String> resErrors = new ArrayList<String>();
    for(ObjectError error : errors.getBindingResult().getAllErrors()){
        resErrors.add(error.getCode());
    }
    response.setStatus(HttpServletResponse.SC_INTERNAL_SERVER_ERROR);
    throw new BusinessException("E000001", "VALIDATION");
}

customer.java（模型）：

package test.business.model;
import javax.validation.constraints.NotNull;
import javax.validation.constraints.Size;

import org.hibernate.validator.constraints.Range;

public class Customer {
    @Size(min = 0, max = 3)
    public String id;

    @NotNull
    @Size(min = 1)
    public String name;

    @NotNull
    @Range(min = 10, max = 99)
    public Integer age;

    public String updateTime;

    public String getId() {
        return id;
    }

    public void setId(String id) {
        this.id = id;
    }

    public String getName() {
        return name;
    }

    public void setName(String name) {
        this.name = name;
    }

    public Integer getAge() {
        return age;
    }

    public void setAge(Integer age) {
        this.age = age;
    }

    public String getUpdateTime() {
        return updateTime;
    }

    public void setUpdateTime(String updateTime) {
        this.updateTime = updateTime;
    }
}

json数据：

1.{"name":"ken","age":11,"updateTime":"2013-06-18"}
2.{"name":"ken","age":"","updateTime":""}
3.{"name":"ken","age":"joe","updateTime":""}

我可以捕获HttpMessageNotReadableException并进行处理。

错误处理已更改的方法。

    @ExceptionHandler
@ResponseStatus(value = HttpStatus.BAD_REQUEST)
@ResponseBody
public void ajaxValidationErrorHandle(Exception errors , HttpServletResponse response) throws BusinessException {
    if(errors instanceof MethodArgumentNotValidException){
        MethodArgumentNotValidException mane = (MethodArgumentNotValidException)errors;
        for(ObjectError error : mane.getBindingResult().getAllErrors()){
            resErrors.add(error.getCode());
        }
    }
    if(errors instanceof HttpMessageNotReadableException){
        JsonMappingException jme = (JsonMappingException)errors.getCause();
        List<Reference> errorObj = jme.getPath();
        for(Reference r : errorObj){
            System.out.println(r.getFieldName());
        }
    }
・・・

但是，继承来创建基类或在所有控制器中编写这段代码感觉我没有看到spring的设计概念，因为它决定在那里处理以创建一个新的ExceptionResolver。

public class OriginalExceptionHandler extends SimpleMappingExceptionResolver {

@Override
public ModelAndView resolveException(HttpServletRequest request, HttpServletResponse response, Object o, Exception e) {
    ModelAndView m = null;
    StringBuilder exceptionMessage = new StringBuilder(ajaxDefaultErrorMessage) ;
    if(e instanceof BusinessException){
                   ・・・
    }else if(e instanceof HttpMessageNotReadableException){
        Throwable t = e.getCause();
        if(t instanceof JsonMappingException){
            JsonMappingException jme = (JsonMappingException)t;
            List<Reference> errorObj = jme.getPath();
            for(Reference r : errorObj){
                exceptionMessage.append("VE9999:Unmatched Type Error!!("+r.getFieldName()+")");
            }
        }else{
            exceptionMessage.append(e+"\n"+o.toString());
        }
    }else if(e instanceof MethodArgumentNotValidException){
        MethodArgumentNotValidException mane = (MethodArgumentNotValidException)e;
        for(ObjectError error : mane.getBindingResult().getAllErrors()){
            if(error instanceof FieldError){
                FieldError fe = (FieldError) error;
                exceptionMessage.append("VE0001:Validation Error!!"+fe.getField()+"-"+fe.getDefaultMessage());
            }else{
                exceptionMessage.append("VE0001:Validation Error!!"+error.getDefaultMessage());
            }
        }
    }else{
                 ・・・

    <bean class="test.core.OriginalExceptionHandler" p:order="1">
    <property name="exceptionMappings">
        <props>
            <prop key="sample.core.BusinessException">
                ExceptionPage
            </prop>
            <prop key="test.core.LoginSessionException">
                LoginSessionException
            </prop>
        </props>
    </property>
    <property name="defaultErrorView" value="error" />
</bean>

谢谢，

Answer 1

数据绑定（将请求映射到对象）是一个独立于数据验证的过程。在Spring中，数据绑定可能会因其自身的绑定错误而导致总体验证错误。

Spring的标准WebDataBinder支持绑定错误，当使用@ModelAttribute注释方法参数时，就会出现绑定错误

对于@RequestBody注释，使用了一种完全不同的机制--HttpMessageConverter（在您的例子中，可能是MappingJackson2HttpMessageConverter)。当JSON解组失败时，将引发HttpMessageNotreadableException异常。