从字符串数组中移除元素[重复]

Question

我创建了一个函数来删除数组中的一个特定元素，但正在努力解决的问题是，当我们从s.next（）中获得要删除的元素的值时，它不是删除，而是当我们已经为它初始化了一个值时，它是删除

例如，我们有一个函数remove

 public static String[] remove(String[] element, String value) {

        int validSize = 0;
        String[] n_elements = new String[0];
        for (int i = 0; i < element.length; i++) {
            if (element[i] == value) {
                element[validSize] = element[i];
                validSize++;
            }

            n_elements = new String[validSize];
            if (validSize >= 0) System.arraycopy(element, 0, n_elements, 0, validSize);


        }

        return n_elements;
    }

public static void main(String[] args) {

 
    String[] group_A = {"Alexandr", "Ahmed", "Maria", "elf", "Omar", "Mariam"};

    Scanner s  = new Scanner(System.in);     

    System.out.println(Arrays.toString(group_A));

    String value = "elf";

    group_A = remove(group_A,value);
    System.out.println(Arrays.toString(group_A));
}

[Alexandr, Ahmed, Maria, elf, Omar, Mariam]
[Alexandr, Ahmed, Maria, Omar, Mariam]

 String value = s.next();

[Alexandr, Ahmed, Maria, elf, Omar, Mariam]
elf
[Alexandr, Ahmed, Maria, elf, Omar, Mariam]

Answer 1

您的代码漏掉了一个“！”在条件之前，您需要使用。equals（）而不是“==”：

public static String[] remove(String[] element, String value) {

        int validSize = 0;
        String[] n_elements = new String[0];
        for (int i = 0; i < element.length; i++) {
            if (! element[i] .equals( value )) {
                element[validSize] = element[i];
                validSize++;
            }
            n_elements = new String[validSize];
            if (validSize >= 0) System.arraycopy(element, 0, n_elements, 0, validSize);
        }
        return n_elements;
    }

public static void main(String[] args) throws IOException {
     String[] group_A = {"Alexandr", "Ahmed", "Maria", "elf", "Omar", "Mariam"};
        Scanner s  = new Scanner(System.in);     
        System.out.println(Arrays.toString(group_A));
        String value = s.nextLine();
        //we already initialized a value for it
        group_A = remove(group_A,value);
        System.out.println(Arrays.toString(group_A));
}