带WebSocket的Spring安全-禁止403

Question

我在Spring实现了WebSocket。一切正常，但最近我决定实施SpringSecurity。

我的MessageBroker看起来像：

@Configuration
@EnableWebSocketMessageBroker
@Component("messageBroker")
public class MessageBroker implements WebSocketMessageBrokerConfigurer {

    @Override
    public void registerStompEndpoints(StompEndpointRegistry stompEndpointRegistry) {
        stompEndpointRegistry.addEndpoint("/graphs").withSockJS();
    }

    @Override
    public void configureMessageBroker(MessageBrokerRegistry messageBrokerRegistry) {
    }

    @Override
    public void configureClientInboundChannel(ChannelRegistration channelRegistration) {
    }

    @Override
    public void configureClientOutboundChannel(ChannelRegistration channelRegistration) {
    }

    @Override
    public boolean configureMessageConverters(List<MessageConverter> messageConverters) {
        messageConverters.add(new MappingJackson2MessageConverter());
        return false;
    }

}

我的JS客户看起来像这样：

var socket = new SockJS('/server/graphs');
var client = Stomp.over(socket);

client.connect({}, function (frame) {
    client.subscribe("/data", function (message) {
        console.log('GET MESSAGE :' + message.body);
        var test = JSON.parse(message.body);
        var point = [ (new Date()).getTime(), parseInt(25) ];
        var shift = randomData.data.length > 60;
        randomData.addPoint(point, true, shift);
    });

});

Spring Security配置：

<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
       xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
       xmlns:security="http://www.springframework.org/schema/security"
       xsi:schemaLocation="http://www.springframework.org/schema/beans
       http://www.springframework.org/schema/beans/spring-beans.xsd
       http://www.springframework.org/schema/security
       http://www.springframework.org/schema/security/spring-security.xsd">

    <security:http auto-config='true' use-expressions="true" disable-url-rewriting="true">
        <security:intercept-url pattern="/login/**" access="isAnonymous()"/>
        <security:intercept-url pattern="/index/**" access="isAuthenticated()" />
        <security:intercept-url pattern="/volumegraph/**" access="isAuthenticated()" />
        <security:intercept-url pattern="/graphs/**" access="permitAll()" />
        <security:intercept-url pattern="/graphs/**/**" access="permitAll()" />
        <security:form-login login-page="/" login-processing-url="/" authentication-failure-url="/" always-use-default-target="true"/>
        <security:csrf/>
        <security:logout logout-success-url="/login"/>
        <security:headers>
            <security:frame-options></security:frame-options>
        </security:headers>
    </security:http>

    <security:authentication-manager>
        <security:authentication-provider>
            <security:user-service>
                <security:user name="user" password="password" authorities="ROLE_USER"/>
            </security:user-service>
        </security:authentication-provider>
    </security:authentication-manager>

</beans>

通过我的JS客户端订阅后，我收到：

Opening Web Socket...
sockjs.js:1213 WebSocket connection to 'ws://localhost:8080/server/graphs/651/kyzdihld/websocket' failed: Error during WebSocket handshake: Unexpected response code: 404
sockjs.js:807 POST http://localhost:8080/server/graphs/651/zx7zdre7/xhr_streaming 403 (Forbidden)AbstractXHRObject._start @ sockjs.js:807(anonymous function) @ sockjs.js:834
sockjs.js:807 POST http://localhost:8080/server/graphs/651/o6eg5ikc/xhr 403 (Forbidden)AbstractXHRObject._start @ sockjs.js:807(anonymous function) @ sockjs.js:834
stomp.js:122 Whoops! Lost connection to undefined

所以我决定在安全配置中添加此代码：

<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
       xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
       xmlns:security="http://www.springframework.org/schema/security"
       xsi:schemaLocation="http://www.springframework.org/schema/beans
       http://www.springframework.org/schema/beans/spring-beans.xsd
       http://www.springframework.org/schema/security
       http://www.springframework.org/schema/security/spring-security.xsd">

<security:websocket-message-broker>
    <!--<security:intercept-message pattern="/graphs/**" access="permitAll()"/>-->
    <security:intercept-message pattern="/**" access="permitAll()"/>
    <security:intercept-message type="SUBSCRIBE" access="permitAll()"/>
    <security:intercept-message type="CONNECT" access="permitAll()"/>
</security:websocket-message-broker>

</beans>

但在那之后我收到这种错误：

NoSuchBeanDefinitionException: No bean named 'springSecurityMessagePathMatcher' is defined

我不知道如何定义这样的bean，所以我创建了以下类：

@Configuration
public class WebSocketSecurityConfig extends AbstractSecurityWebSocketMessageBrokerConfigurer {

    protected void configureInbound(MessageSecurityMetadataSourceRegistry messages) {
        messages.simpDestMatchers("/graphs/*").permitAll();
        messages.simpDestMatchers("/**").permitAll();
    }
}

但在编译期间，我收到这种错误：

java: cannot access org.springframework.beans.factory.SmartInitializingSingleton
  class file for org.springframework.beans.factory.SmartInitializingSingleton not found

我真的不知道如何解决这个问题：（我必须补充一点，我正在使用SpringCore4.0.1.RELEASE和SpringMessaging4.0.1.RELEASE。所有与SpringSecurity相关的lib都在4.0.1.RELEASE版本中。

Answer 1

为了使其正常工作，您必须修改

<websocket:message-broker  application-destination-prefix="/app" user-destination-prefix="/user" >
 <websocket:stomp-endpoint path="/websocketEndPoint" >
 <websocket:handshake-handler ref="astalavista" />
 <websocket:simple-broker prefix="/topic , /queue"  /> 
 <websocket:client-inbound-channel >
   <websocket:interceptors>
   <!--This will reference your interceptor that you have defined in you security XML-->
      <ref bean="interceptor"/>
   </websocket:interceptors>
 </websocket:client-inbound-channel>
</websocket:message-broker>