403禁止-Spring安全

Question

我正在尝试使用Spring security保护我的网站，但我一直收到403禁止的错误。我在网上看到过很多帖子，但没有一篇是针对我的情况写的。

我正在使用Springboot构建一个后端RESTapi，并用Postman进行测试。

我已禁用http。csrf（）。禁用（） 但仍然存在403错误。

我可以访问所有用户都有权限的部分，它还可以识别我是否放置了错误的凭据，但当我尝试访问只有角色为ADMIN或user的用户才有权限的部分时，我立即出现以下错误。

{
    "timestamp": "2020-08-30T02:08:36.033+00:00",
    "status": 403,
    "error": "Forbidden",
    "message": "",
    "path": "/secure/auth/addUser"
 }

安全Configuration.java

@Configuration
@EnableWebSecurity
@EnableGlobalMethodSecurity(prePostEnabled = true)
public class SecurityConfiguration extends WebSecurityConfigurerAdapter {

    @Autowired
    private UserDetailsService userDetailsService;

   @Override
    protected void configure(AuthenticationManagerBuilder auth) throws Exception {
        auth
                .userDetailsService(userDetailsService)
                .passwordEncoder(encodePWD());
    }

    @Override
    protected void configure(HttpSecurity http) throws Exception {

        http.csrf().disable();
        http
                .httpBasic()
                .and()
                .authorizeRequests()
                .antMatchers("/rest/**").permitAll()
                .and()
                .authorizeRequests()
                .antMatchers("/secure/**").hasAnyRole("ADMIN")
                .anyRequest().authenticated()
                .and()
                .formLogin()
                .permitAll();


    }

    @Bean
    public BCryptPasswordEncoder encodePWD() {
        return new BCryptPasswordEncoder();
    }


}

CustomUserDetailsService。JAVA

@Service
public class CustomUserDetailsService implements UserDetailsService {

    @Autowired
    private UserRepository userRepository;

    @Override
    public UserDetails loadUserByUsername(String username) throws UsernameNotFoundException {
        User user = userRepository.findByUsername(username);
        CustomUserDetails userDetails = null;

        if(user != null){
            userDetails = new CustomUserDetails();
            userDetails.setUser(user);
        }else{
            throw new UserNotFoundException("User doesn't exist with this username: " + username);
        }
        return userDetails;

    }

}

CustomUserDetails。JAVA

@Getter
@Setter
public class CustomUserDetails implements UserDetails {

    private User user;

    @Override
    public Collection<? extends GrantedAuthority> getAuthorities() {
        return user.getRoles().stream().map(role -> new SimpleGrantedAuthority("ROLE_" + role)).collect(Collectors.toSet());

    }
    
    @Override
    public String getPassword() {
        return user.getPassword();
    }

    @Override
    public String getUsername() {
        return user.getUsername();
    }

    @Override
    public boolean isAccountNonExpired() {
        return true;
    }

    @Override
    public boolean isAccountNonLocked() {
        return true;
    }

    @Override
    public boolean isCredentialsNonExpired() {
        return true;
    }

    @Override
    public boolean isEnabled() {
        return true;
    }

}

java

@RequestMapping("/secure/auth/")
public class UserController {

 @Autowired
    private BCryptPasswordEncoder passwordEncoder;

 @PreAuthorize("hasAnyRole('ADMIN')")
    //POST method for adding one user
    @PostMapping("/addUser")
    public User addUser(@RequestBody User user){
        String pwd = user.getPassword();
        String encriptPwd = passwordEncoder.encode(pwd);
        user.setPassword(encriptPwd);
        return service.saveUser(user);
    }

//other code needed
}

BookContoller.java

@RestController
@RequestMapping("/rest/auth")
public class BookContoller {

    @Autowired
    private BookService service;

    //GET method display all books
    @GetMapping("/books")
    public List<Book> findAllBooks(){
        return service.getAllBooks();
    }

使现代化

当我调试部分代码时

return user.getRoles().stream().map(role -> new SimpleGrantedAuthority("ROLE_" + role)).collect(Collectors.toSet());

我回到我用来登录的用户...

User(id=1, name=chad, surname=huskins, username=chad, email=[e-mail], password=$2a$10$SMH1T6fQ4HqzTAop.XOR/eDlfKzyjSkGGsT/qDCy1JYnncpdkqv32, roles=[Role(id=1, role=ADMIN)])

使用者JAVA

public class User {

    @Id
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    private Integer id;

    private String name;
    private String surname;
    private String username;
    private String email;
    private String password;

    //@OneToMany(mappedBy = "user", cascade = CascadeType.ALL)
    //private List<Rent> rent = new ArrayList<>();

    @OneToMany(cascade = CascadeType.ALL, fetch = FetchType.EAGER)
    @JoinTable(name = "user_role", joinColumns = @JoinColumn(name = "user_id"), inverseJoinColumns = @JoinColumn(name = "role_id"))
    private Set<Role> roles;
    
    public Set<Role> getRoles() {
        return roles;
    }

    public void setRoles(Set<Role> roles) {
        this.roles = roles;
    }
}

Role.java

@Table(name = "Roles")
public class Role {

    @Id
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    private Integer id;
    private String role;
}




Answer 1

使用newsimplegrantedauthority（“ROLE\uu”ROLE.getRole（））而不是newsimplegrantedauthority（“ROLE\uu”ROLE））