如何将ajv与依赖的JSON-模式一起使用？

Question

我尝试使ajv使用两个JSON-Schema，一个依赖于另一个。下面是我的模式的一个示例（简化）：

json

{
    "$schema":"http://json-schema.org/draft-04/schema#",
    "$id": "http://a.site.org/schemas/types.json",
    "type": "object",
    "definitions": {
        "gender":{"enum": ["male", "female"]}
    },
    "properties":{
        "gender":{"$ref": "#/definitions/gender"}
    }
}

{
"$schema":"http://json-schema.org/draft-04/schema#",
"$id": "http://a.site.org/schemas/definitions.json",
"definitions": {
    "person":{
        "type":"object",
        "properties": {
            "username":{"type":"string"},
            "password": {"type":"string"},
            "name":{"type":"string"},
            "surname":{"type":"string"},
            "sex":{"$ref": "types.json#/properties/gender"},
            "email":{"type":"string", "format":"email"}
        },
        "required":["name", "surname", "sex", "email"]
    }
},
"type":"object",
"properties": {
    "person": {"$ref": "#/definitions/person"}
    }
}

import Ajv, {JSONSchemaType, DefinedError} from "ajv"
import {Gender} from "./types"
import {Person} from "./definitions";
const ajv = new Ajv()

const types : JSONSchemaType<Gender>= require("../types.json");
const PersonSchema : JSONSchemaType<Person> = require('../definitions.json').definitions.person;

const isPerson = ajv.addSchema(types).compile(PersonSchema);
const riccardo:Person={name: "Riccardo", surname: "surname", sex: "male", email: "[e-mail]"};
const personValid = isPerson(riccardo);
if (!personValid) console.log(isPerson.errors)

错误：没有带有键或引用“http://json-schema.org/draft-04/schema#”的模式

更新：如果我从types.json中删除“$schema…”，我得到的错误是：

MissingReferror：无法从id#中解析引用types.json#/definitions/gender

Answer 1

从版本7开始，对draft-04的支持已经删除。如果要使用draft-04，则需要使用AJV的版本6。