Android--如何获取Flavior的ApplicationId

Question

    productFlavors {
    free {
        applicationId "com.example.free"
        resValue "string", "app_name", "Free App"
        versionName "1.0-free"
    }
    paid {
        applicationId "com.example.paid"
        resValue "string", "app_name", "Paid App"
        versionName "1.0-paid"
    }

    if(whateverpackageid.equals("paid")) {
      // Do something or trigger some premium functionality.
    } 

Answer 1

我将在您的产品口味中使用构建配置变量。类似于：

productFlavors {
    free {
        applicationId "com.example.free"
        resValue "string", "app_name", "Free App"
        versionName "1.0-free"
        buildConfigField "boolean", "PAID_VERSION", "false"
    }
    paid {
        applicationId "com.example.paid"
        resValue "string", "app_name", "Paid App"
        versionName "1.0-paid"
        buildConfigField "boolean", "PAID_VERSION", "true"
    }
}

则在生成之后,您可以使用：

if (BuildConfig.PAID_VERSION) {
    // do paid version only stuff
}

在添加属性之后，您可能必须在gradle上执行同步/构建，然后才能编译和导入gradle代表您生成的BuildConfig类。