如何在SpringREST控制器中获取原始JSON主体？

Question

下面的API接受来自客户端的json字符串，并将其映射到电子邮件对象中。如何将请求正文（电子邮件）作为原始字符串获取？（我需要原始字符串和键入版本的email参数）

PS：这个问题不是重复的：如何在SpringREST控制器中访问普通json主体？

@PostMapping(value = "/mailsender")
public ResponseEntity<Void> sendMail(@RequestBody Email email) {
    //...
    return new ResponseEntity<>(HttpStatus.OK);
}

Answer 1

您可以使用GSON库创建字符串类型的json

Gson gson = new Gson();

@PostMapping(value = "/endpoint")
public ResponseEntity<Void> actionController(@RequestBody Car car) {
    //...
    log.info("Object as String: " + this.gson.toJson(car));
    return new ResponseEntity<>(HttpStatus.OK);
}

Answer 2

Spring在后面使用Jackson，您可以使用它将其序列化为字符串。像这样：

@Autowired private ObjectMapper jacksonMapper;

@PostMapping(value = "/mailsender")
public ResponseEntity<Void> sendMail(@RequestBody Email email) {
    //...
    log.info("Object as String: " + jacksonMapper.writeValueAsString(email));
    return new ResponseEntity<>(HttpStatus.OK);
}

Answer 3

您可以用多种方法来实现，清单2

 1. **Taking string as the paramater**,
     @PostMapping(value = "/mailsender")
        public ResponseEntity<Void> sendMail(@RequestBody String email) {
            //... the email is the string can be converted to Json using new JSONObject(email) or using jackson.
            return new ResponseEntity<>(HttpStatus.OK);
        }

 2. **Using Jackson** 
         @PostMapping(value = "/mailsender")
            public ResponseEntity<Void> sendMail(@RequestBody Email email) {
                //...
                ObjectMapper mapper = new ObjectMapper(); 
                String email = mapper.writeValueAsString(email); //this is in string now
                return new ResponseEntity<>(HttpStatus.OK);
            }