Java基本高：低猜谜游戏帮助（循环）

Question

我已经停止编程一段时间了。大概4年左右，我只是想搞乱它，所以我决定做一个高：低数字猜谜游戏。（猜一个数字1-100，如果你猜得太高或太低，程序会说）我完全忘了我该怎么做：

package highlow;

import java.util.Random;
import java.util.Scanner;

public class guessing {
    public static void main(String[] args){

        Scanner input = new Scanner(System.in);

        Random rand = new Random();
        int tries;
        int correctNum = rand.nextInt(100);

        System.out.println("enter a number 1-100");
        int guess1 = input.nextInt();

        if(guess1 < correctNum){
            System.out.println("number is too low!");
        }
        else if(guess1 > correctNum){
            System.out.println("Number is too high!");
        }
        else if(guess1 == correctNum){
            System.out.println("correct!");
        }
        else{
            System.out.println("not a valid option");
        }


    }

}

Answer 1

您需要将所有内容封装在while循环中，以便它不断重复，直到用户正确猜测：

// Make the scanner, get the random number etc... Put all the setup and
// stuff you don't want to be repeated here

while (true) {
    System.out.println("enter a number 0-99"); // Changed from 1-100 because rand.nextInt(100)
                                               // returns a number between 0 and 99
                                               // You can do correctNum += 1 to make it between 1 and 100
                                               // But put this in before the while loop starts
    int guess1 = input.nextInt();

    if(guess1 < correctNum){
        System.out.println("number is too low!");
    }
    else if(guess1 > correctNum){
        System.out.println("Number is too high!");
    }
    else if(guess1 == correctNum){
        System.out.println("correct!");
        break; // <---- Add this, this will make the loop stop when the 
               //player gets the answer correct and therefore the program will end
    }
    else{
        System.out.println("not a valid option");
    }
}

而循环重复它们内部的内容，直到它们的()中的语句为false。在我们的示例中，循环将永远进行下去，因为true位于()中，但是使用break语句，当用户正确猜测时循环将结束。