如何管理WebSocket、Socket和NodeJS应用程序的端口？

Question

我最终使用了3个不同的端口。777，3000和4000，我似乎仍然没有一个想要的结果。

如何为Socket.io和nodejs应用程序使用相同的端口？即使用端口3000。

var createError = require('http-errors');
var express = require('express');
var app = require('express')();
var http = require('http').Server(express);
var path = require('path');
var cookieParser = require('cookie-parser');
var logger = require('morgan');

var indexRouter = require('./routes/index');
var usersRouter = require('./routes/users');

var io = require('socket.io')(http);
io.listen(4000);
var nsp = io.of('/channel1');
var net = require('net');

var server = net.createServer(function(socket) {
  socket.pipe(socket);
  socket.setEncoding('utf8');
  socket.on("data", function(d) {
    nsp.emit('live-data', d);
    console.log("DATA:", d);
  });
});

server.listen(777, '127.0.0.1');

// view engine setup
app.set('views', path.join(__dirname, 'views'));
app.set('view engine', 'ejs');

app.use(logger('dev'));
app.use(express.json());
app.use(express.urlencoded({ extended: false }));
app.use(cookieParser());
app.use(express.static(path.join(__dirname, 'public')));

app.use('/', indexRouter);
app.use('/users', usersRouter);

// catch 404 and forward to error handler
app.use(function(req, res, next) {
  next(createError(404));
});

// error handler
app.use(function(err, req, res, next) {
  // set locals, only providing error in development
  res.locals.message = err.message;
  res.locals.error = req.app.get('env') === 'development' ? err : {};

  // render the error page
  res.status(err.status || 500);
  res.render('error');
});

module.exports = app;

Answer 1

来自socket.io的官方自述文件

const app = require('express')();
const server = require('http').createServer(app);
const io = require('socket.io')(server);
io.on('connection', () => { /* … */ }); 
server.listen(3000);

这将允许您对express和Socket.io使用相同的端口。