Phonegap/corova社交分享插件，重复推文问题

Question

我正在使用社交分享插件将我的手机应用程序中的消息和图片分享到facebook和twitter，
如果分享成功，应用程序将显示“分享成功”警报，如果插件显示任何错误消息，则显示“分享已取消”
对于facebook来说，这就像一种魅力，但在twitter中却有一个问题。它适用于所有场景，但重复推特（重复推特的人不止一次分享同一条推特）除外。当插件的所有条件都满足（互联网连接、用户身份验证、有效消息）时，这两个警报都会被触发，但手机中的推特应用程序稍后会抛出“重复推特”错误。这里的任何人都请帮助我在触发警报之前找到错误消息。

function shareViaTwitter(id, message, image, url) {
    canShareViaTwitter();
    message = message.replace(/<br *\/?>/gi,'\n');

var successmessage  = window.localStorage.getItem('canshareTwitsuccess');
var errormessage    = window.localStorage.getItem('canshareTwiterror');

if(errormessage != '' && errormessage != 'null' && errormessage != null)
{
    navigator.app.loadUrl('https://play.google.com/store/apps/details?id=com.twitter.android&hl=en', { openExternal:true });
    reloadPage();
}
else
{   
    if(navigator.onLine) {
        var isAndroid = /android/i.test(navigator.userAgent.toLowerCase());

        if(isAndroid) {
            message = (message) ? message : null;
            image = (image) ? image : null;
            url = (url) ? url : null;

            window.plugins.socialsharing.shareViaTwitter(message, image, url, function(msg){}, function(msg){});
            $("#sharingText").html("Shared Successfully");
            $('#sharing-sucess-trigger').trigger('click');
        }
    } else {
        $("#sharingText").html("Shared Failed! \nNo Network Connection");
        $('#sharing-sucess-trigger').trigger('click');
    }
    reloadPage();
}
}

function canShareViaFacebook()
{
    //alert("canshare")
    window.plugins.socialsharing.canShareVia('com.facebook.katana', 'msg', null, null, null, function(fbsuccess){window.localStorage.setItem("canshareFbsuccess", fbsuccess);}, function(fberror){window.localStorage.setItem("canshareFberror", fberror);});
}

function canShareViaTwitter()
{
    //alert("canshare")
    window.plugins.socialsharing.canShareVia('twitter', 'msg', null, null, null, function(twitsuccess){window.localStorage.setItem("canshareTwitsuccess", twitsuccess);}, function(twiterror){window.localStorage.setItem("canshareTwiterror", twiterror);});
}

Answer 1

这个代码真的很奇怪。如果您与以下人员分享推文:

socialsharing.shareViaTwitter(message, file, url, successCallback, errorCallback)

并且您想告诉用户tweet失败了，那么您可以使用errorCallback来提醒用户tweet失败了。

function errorCallback(msg){
    alert(msg);
}

--附加代码--

function shareViaTwitter(id, message, image, url) {
    message = message.replace(/<br *\/?>/gi,'\n');
    canShareViaTwitter(function(){
        if(navigator.onLine) {
            var isAndroid = /android/i.test(navigator.userAgent.toLowerCase());

            if(isAndroid) {
                message = (message) ? message : null;
                image = (image) ? image : null;
                url = (url) ? url : null;

                window.plugins.socialsharing.shareViaTwitter(message, image, url, function(msg){}, function(msg){});
                $("#sharingText").html("Shared Successfully");
                $('#sharing-sucess-trigger').trigger('click');
            }
        }
        else {
            $("#sharingText").html("Shared Failed! \nNo Network Connection");
            $('#sharing-sucess-trigger').trigger('click');
        }
        //why?
        reloadPage();
    },
    function(){
        navigator.app.loadUrl('https://play.google.com/store/apps/details?id=com.twitter.android&hl=en', { openExternal:true });
        reloadPage();
    });
}
function canShareViaTwitter(successCallback, errorCallback)
{
    //alert("canshare")
    window.plugins.socialsharing.canShareVia('twitter', 'msg', null, null, null, function(twitsuccess){window.localStorage.setItem("canshareTwitsuccess", twitsuccess);successCallback();}, function(twiterror){window.localStorage.setItem("canshareTwiterror", twiterror);errorCallback()});
}