按对象类别为多个数组求深度嵌套数组数据之和

Question

我有一个函数返回包含2个数组的2个数组。

[Array(3), Array(3)]

[Array(3), Array(3)]

这些嵌套数组每个包含6个对象

{value: "10.50", category: "a"}, 
{value: "55.50", category: "a"}
{value: "10.50", category: "b"}, 
{value: "35.50", category: "b"},
{value: "15.50", category: "c"},
{value: "45.50", category: "c"}

我正在尝试迭代每个主2数组，并按类别返回嵌套数组的求和值，如下所示：记住，值当前是一个字符串。

[
 [
  {value: "66.00", category: "a"},
  {value: "46.00", category: "b"},
  {value: "61.00", category: "c"},
 ]
]

我已经尝试了下面的，但我似乎不能得到它的权利，我看了许多这样的线程，我知道有吨类似的，但没有任何工作为我目前为止。蒂娅。

我可怜的尝试。

  const x = array.forEach((data) => {
    data.reduce(function (
      acc: any[],
      val: { category: string; value: string }
    ) {
      const o = acc
        .filter(function (obj) {
          return obj.category === val.category;
        })
        .pop() || { category: val.category, value: 0 };

      o.value += parseFloat(String(val.value));
      acc.push(o);
      return acc;
    },
    []);
  });

Answer 1

听起来，您只需分组到一个由category索引的对象中，将值相加，确保将字符串强制为数字，然后将其转换为对象数组：

null

const outerArr = [
  [
    {value: "10.50", category: "a"}, 
    {value: "55.50", category: "a"},
    {value: "10.50", category: "b"}, 
    {value: "35.50", category: "b"},
    {value: "15.50", category: "c"},
    {value: "45.50", category: "c"}
  ],
  // etc
];

const final = outerArr.map((subarr) => {
  const grouped = {};
  for (const { value, category } of subarr) {
    grouped[category] = (grouped[category] || 0) + Number(value);
  }
  return Object.entries(grouped).map(([category, value]) => ({ value: value.toFixed(2), category }));
});
console.log(final);