Spring如何通过XML向Queue注入值

Question

使用Spring框架，我想创建一个类型为Person的bean对象，这个bean对象有一个queue类型为queue的属性

Spring版是4.3

参考文件是https://docs.spring.io/spring/docs/4.3.25.RELEASE/spring-framework-reference/htmlsingle/#beans-工厂级电机

但我找不到队列。

我尝试使用

对象如下

public class People {
    private int id;
    private Queue<Integer> queue;
    // add constructor

    // add get and set
}

应用程序上下文。xml如下所示

<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
       xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
       xsi:schemaLocation="http://www.springframework.org/schema/beans
        https://www.springframework.org/schema/beans/spring-beans.xsd">

    <bean id="..." class="...">
        <property name="queue">
            <bean class="java.util.ArrayDeque">
                //How should I add values to the queue object
            </bean>
        </property>
    </bean>
</beans>




Answer 1

通过参考Spring对collection的支持，

下面的示例演示如何向ArrayDeque添加值。

应用Context.xml

<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xsi:schemaLocation="http://www.springframework.org/schema/beans
        https://www.springframework.org/schema/beans/spring-beans.xsd">

    <bean id="people" class="spring.People">
        <property name="queue">
            <bean class="java.util.ArrayDeque">
                <constructor-arg>
                    <list value-type="java.lang.Integer">
                        <value>1</value>
                        <value>2</value>
                        <value>3</value>
                    </list>
                </constructor-arg>
            </bean>
        </property>
    </bean>
</beans>

主类

package spring;

import org.springframework.context.ApplicationContext;
import org.springframework.context.support.ClassPathXmlApplicationContext;

public class InjectQueueApplication {
    public static void main(String[] args) {
        ApplicationContext context = new ClassPathXmlApplicationContext("applicationContext.xml");
        People people = context.getBean("people", People.class);
        System.out.println(people.getQueue().toString());
    }
}