具有AuthorizationGrantType.PASSWORD的Spring授权服务器

Question

我想用Spring授权服务器项目构建一个授权服务器。现在我想使用AuthorizationGrantType.PASSWORD.

我从Spring授权服务器项目的示例中开发了一个演示项目。但是，当我尝试使用http://localhost:9000/oauth2/token?grant_type=password获取令牌时

我在这里错过了什么？

依赖项：spring boot starter web、spring boot-starter安全性、spring-security-oauth2-authorization-server（版本：0.2.2）

AuthorizationServerConfig类：

import java.security.*;
import java.security.interfaces.*;
import java.util.UUID;
import org.springframework.context.annotation.*;
import org.springframework.security.oauth2.core.*;
import org.springframework.security.oauth2.server.authorization.client.*;
import org.springframework.security.oauth2.server.authorization.config.ProviderSettings;
import com.nimbusds.jose.jwk.RSAKey;
import com.nimbusds.jose.jwk.*;
import com.nimbusds.jose.jwk.source.JWKSource;
import com.nimbusds.jose.proc.SecurityContext;

@Configuration(proxyBeanMethods = false)
public class AuthorizationServerConfig {
    
    @Bean
    public RegisteredClientRepository registeredClientRepository() {
        RegisteredClient registeredClient = RegisteredClient.withId(UUID.randomUUID().toString())
                .clientId("client1")
                .clientSecret("{noop}secret")
                .clientAuthenticationMethod(ClientAuthenticationMethod.CLIENT_SECRET_BASIC)
                .authorizationGrantType(AuthorizationGrantType.PASSWORD)
                .authorizationGrantType(AuthorizationGrantType.REFRESH_TOKEN)
                .build();
        return new InMemoryRegisteredClientRepository(registeredClient);
    }
    
    @Bean
    public ProviderSettings providerSettings() {
        return ProviderSettings.builder()
                .issuer("http://auth-server:9000")
                .build();
    }
    
    @Bean
    public JWKSource<SecurityContext> jwkSource() {
        RSAKey rsaKey = generateRsa();
        JWKSet jwkSet = new JWKSet(rsaKey);
        return (jwkSelector, securityContext) -> jwkSelector.select(jwkSet);
    }
    
    private static RSAKey generateRsa() {
        KeyPair keyPair = generateRsaKey();
        RSAPublicKey publicKey = (RSAPublicKey) keyPair.getPublic();
        RSAPrivateKey privateKey = (RSAPrivateKey) keyPair.getPrivate();
        return new RSAKey.Builder(publicKey)
                .privateKey(privateKey)
                .keyID(UUID.randomUUID().toString())
                .build();
    }
    
    private static KeyPair generateRsaKey() {
        KeyPair keyPair;
        try {
            KeyPairGenerator keyPairGenerator = KeyPairGenerator.getInstance("RSA");
            keyPairGenerator.initialize(2048);
            keyPair = keyPairGenerator.generateKeyPair();
        } catch (Exception ex) {
            throw new IllegalStateException(ex);
        }
        return keyPair;
    }    
}

DefaultSecurityConfig类：

import org.springframework.context.annotation.Bean;
import org.springframework.security.config.annotation.web.builders.HttpSecurity;
import org.springframework.security.config.annotation.web.configuration.EnableWebSecurity;
import org.springframework.security.core.userdetails.*;
import org.springframework.security.provisioning.InMemoryUserDetailsManager;
import org.springframework.security.web.SecurityFilterChain;

@EnableWebSecurity
public class DefaultSecurityConfig {
    
    @Bean
    SecurityFilterChain defaultSecurityFilterChain(HttpSecurity http) throws Exception {
        http
                .csrf().disable()
                .cors().disable()
                .authorizeRequests(authorizeRequests ->
                        authorizeRequests
                                .anyRequest()
                                .authenticated()
                );
        return http.build();
    }
    
    @Bean
    public UserDetailsService userDetailsService() {
        UserDetails userDetails = User.withDefaultPasswordEncoder()
                .username("user")
                .password("pass")
                .roles("USER")
                .build();
        return new InMemoryUserDetailsManager(userDetails);
    }    
}

日志中有这样一条信息，我发现它可能是相关的:

o.s.s.w.a.i.FilterSecurityInterceptor    : Failed to authorize filter invocation [POST /oauth2/token?grant_type=password&username=user&password=pass] with attributes [authenticated]

Answer 1

你可以实现一个密码授予仿真过滤器，请看我的例子:https://github . com/andreygrigoriev/spring _ authorization _ server _ password _ grant

Answer 2

似乎不支持密码grant_type。可能这就是我出错的原因。

来源：https://github.com/spring-projects/spring-authorization-server/issues/126