从响应分析日期[重复]

Question

我使用此代码获取过期日期：

        String nameToQuery = "godaddy.com";

        WhoisClient whoisClient = new WhoisClient();
        whoisClient.connect(WHOIS_SERVER, WHOIS_PORT);
        String results = whoisClient.query(nameToQuery);
        if (StringUtils.strip(results).startsWith("QUOTA_EXCEEDED")) {
            throw new Exception();
        }
        if (StringUtils.strip(results).startsWith("No match for")) {
            throw new Exception();
        }
        if (StringUtils.strip(results).startsWith("DOMAIN_NOT_FOUND")) {
            throw new Exception();
        }
        whoisClient.disconnect();

        int idx = results.toLowerCase().indexOf("registry expiry date:");
        if (idx != -1) {
            results = results.substring(idx+21).trim();
            System.out.println("!!!!!!!!!" + results);
        }

我得到的答复是：

!!!!!!!!!2021-11-01T11:59:59Z

如何将结果转换为Java LocalDateTime并与当前系统时间进行比较？

Answer 1

您需要首先指定您的日期时间模式（基于您的代码似乎是ISO_ZONED_DATE_TIME)。这就像：

DateTimeFormatter dateTimePattern = DateTimeFormatter.ISO_ZONED_DATE_TIME // replace it with any date time pattern if it's difference date time pattern, for example replace it with DateTimeFormatter.ofPattern("yyyy-MM-dd HH:mm:ss") if it's your custom pattern.
LocalDateTime now = LocalDateTime.now();
LocalDateTime yourResult = LocalDateTime.parse(dateFromResponseString, dateTimePattern);
boolean equals = now.isEqualTo(yourResult); // to check if it's equals or not
int compare = now.compareTo(yourResult); // to compare it, return -1 if it's less, 0 if equals or 1 if it's greater

Answer 2

String dateString = "2021-11-01T11:59:59Z";
Instant instant = Instant.parse(dateString);
LocalDateTime localDateTime = LocalDateTime.ofInstant(instant, ZoneId.of(ZoneOffset.UTC.getId()));

Z表示现在是UTC时间。因此首先将其转换为Instant&然后转换为LocalDateTime。