对象数组获得具有唯一ID的total

Question

因此，我有一个名为playerscoresdata的对象数组，我需要获得每个球员的得分和犯规总数。

我的问题是我认为我使用了太多的迭代/循环

有没有更干净的解决方案？

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const playerScoresData = [
  {
    playerId: '1',
    score: 20,
    foul: 3
  },
  {
    playerId: '1',
    score: 5,
    foul: 2
  },
  {
    playerId: '2',
    score: 30,
    foul: 1
  },
  {
    playerId: '2',
    score: 10,
    foul: 3
  }
]

const main = () => {
  let stats = []
  let newData = {}
  const uniqPlayerIds = [...new Set(playerScoresData.map(item => item.playerId))]

  for (var x = 0; x < uniqPlayerIds.length; x++) {
    newData = {
      playerId: uniqPlayerIds[x],
      totalScores: 0,
      totalFouls: 0
    }
    let filteredData = playerScoresData.filter(data => data.playerId === uniqPlayerIds[x])
    for (var y = 0; y < filteredData.length; y++) {
      newData.totalScores += filteredData[y].score
      newData.totalFouls += filteredData[y].foul
    }
    stats.push(newData)
  }
  return stats
}

console.log(main())

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Answer 1

您可以简单地使用.reduce()方法，以更方便的方式聚合数据：

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const playerScoresData = [
  {
    playerId: '1',
    score: 20,
    foul: 3
  },
  {
    playerId: '1',
    score: 5,
    foul: 2
  },
  {
    playerId: '2',
    score: 30,
    foul: 1
  },
  {
    playerId: '2',
    score: 10,
    foul: 3
  }
];

const result = playerScoresData.reduce((acc, item) => {
  acc[item.playerId] = acc[item.playerId] || {tScore:0, tFoul: 0}; // set default value if missing
  acc[item.playerId].tScore += item.score;
  acc[item.playerId].tFoul += item.foul;
  return acc;
}, {});

console.log(result);