使用现有节点在spring数据中创建Neo4j关系

Question

我试图在Neo4j中创建节点之间的关系。我正在使用Neo4J（2.1.8社区）

我试图创建以下关系。

创建一个新的员工（节点），它将向DB中的Manager（节点）报告（空关系）（按名称搜索）。我使用了下面的查询。

public interface EmployeeRepository extends GraphRepository<Employee> {

@Query("START employee=node:({0}), manager=node:Employee(name={1}) CREATE employee-[:REPORTS_TO]->manager")
void addNewEmployee(Employee employee, String managerName);}

我得到了下面的错误。

Caused by: org.springframework.dao.InvalidDataAccessResourceUsageException: Error executing statement START employee=node:({0}), manager=node:Employee(name={1}) CREATE employee-[:REPORTS_TO]->manager; nested exception is Invalid input '(': expected whitespace or an identifier (line 1, column 21)
"START employee=node:({0}), manager=node:Employee(name={1}) CREATE employee-[:REPORTS_TO]->manager"
                     ^

谁能告诉我这个问题出了什么问题？另外，如果这不是使用GraphRespository创建关系的正确方法，那么我还可以使用什么来实现同样的目的呢。

提前感谢。

注意：我用它来学习Spring Data for Neo4j中的查询。其中显示了基本查询。

更新：员工类

@NodeEntity
public class Employee {

@GraphId
private Long id;
private String name;
private String department;

@RelatedTo(type = "REPORTS_TO")
private Employee reportsTo;

@RelatedTo(type = "REPORTS_TO", direction = Direction.INCOMING)
Set<Employee> directReport;

public Employee() {
}

public Employee(String name, String department) {
    this.name = name;
    this.department = department;
}

public Long getId() {
    return id;
}

public String getName() {
    return name;
}

public void setName(String name) {
    this.name = name;
}

public String getDepartment() {
    return department;
}

public void setDepartment(String department) {
    this.department = department;
}

public Employee getReportsTo() {
    return reportsTo;
}

public void setReportsTo(Employee reportsTo) {
    this.reportsTo = reportsTo;
}

public Set<Employee> getDirectReport() {
    return directReport;
}

public void setDirectReport(Set<Employee> directReport) {
    this.directReport = directReport;
}

@Override
public int hashCode() {
    return super.hashCode();
}

@Override
public boolean equals(Object obj) {
    return super.equals(obj);
}

@Override
public String toString() {
    return "Employee{" + "id=" + id + ", name=" + name + ", department=" + department + '}';
}
}

Answer 1

请出示员工的定义！

您也可以使用模板。createRelationshipBetween（nodeOrEntity，nodeOrEntity2，type）

对于您的示例，这应该是可行的：

公共接口员工存储库扩展GraphRepository{

@Query("MATCH (employee:Employee), (manager:Employee) 
       WHERE id(employee) = {0} AND manager.name = {1}
       CREATE employee-[:REPORTS_TO]->manager")
void addNewEmployee(Employee employee, String managerName);
}

也许更好地使用，雇员作为雇员的数据容器/地图，或者直接传入名称：

@Query("MATCH (employee:Employee), (manager:Employee) 
       WHERE employee.name = {0}.name AND manager.name = {1}
       CREATE employee-[:REPORTS_TO]->manager")
void addNewEmployee(Employee employee, String managerName);
}