在具有许多属性的Spring Data JPA中过滤结果的最佳解决方案是什么？

Question

public interface ProductRepository extends JpaRepository<Product, Long> {
   //..... other methods

Page<Product> findByCategoriesContainingAndSalepriceBetween(List<Category> categories, Float minprice, Float maxprice, PageRequest pagerequest);

Page<Product> findByCategoriesContaining(List<Category> categories, PageRequest pagerequest);

Page<Product> findByCategoriesContainingAndSizeIn(List<Category> categories,Int[] sizes, PageRequest pagerequest);

Page<Product> findByCategoriesContainingAndSizeInAndSalepriceBetween(List<Category> categories,Float minprice, Float maxprice, PageRequest pagerequest);

Answer 1

我不同意QueryDSL会导致大量额外的代码。下面是QueryDSL的一些测试代码：

存储库定义：

public interface UserRepository extends PagingAndSortingRepository<User, Long>, QueryDslPredicateExecutor<User> {

    public User findOne(Predicate predicate);

    public List<User> findAll(Predicate predicate);
}

基于各种属性及其组合的测试代码：

 @Test
    public void testFindByEmailAddress() {
        User user = repository.findOne(QUser.user.emailAddress.eq("[e-mail]"));
        Assert.assertNotNull(user);
        Assert.assertEquals("Jack", user.getForename());
        Assert.assertEquals("Hamilton", user.getSurname());
    }

    @Test
    public void testFindByGender() {
        List<User> users = repository.findAll(QUser.user.gender.eq(Gender.M));
        Assert.assertEquals(4, users.size());

        users = repository.findAll(QUser.user.gender.eq(Gender.F));
        Assert.assertEquals(2, users.size());
    }

    @Test
    public void testFindByCity() {

        List<User> users = repository.findAll(QUser.user.address.town.eq("Edinburgh"));
        Assert.assertEquals(2, users.size());

        users = repository.findAll(QUser.user.address.town.eq("Stirling"));
        Assert.assertEquals(1, users.size());
    }

    @Test
    public void testFindByGenderAndCity() {
        List<User> users = repository.findAll(QUser.user.address.town.eq("Glasgow").and(QUser.user.gender.eq(Gender.M)));
        Assert.assertEquals(2, users.size());

        users = repository.findAll(QUser.user.address.town.eq("Glasgow").and(QUser.user.gender.eq(Gender.F)));
        Assert.assertEquals(1, users.size());
    }