我需要21点游戏的帮助，打印出两张牌

Question

我有一个黑杰克游戏，我需要制作，它被分离成两个文件，一个处理牌洗牌和另一个是关于实际的游戏

我的问题是，我可以得到代码，以打印两张牌的球员和经销商，虽然我需要打印的格式，如这样

玩家的手牌是3：1的球杆2的红心

不是这样的

['1c','2h']

显示总数并将卡片分开

这是管理游戏的第一个文件，另一个是纸牌

import playing_cards
import random
player_hand = []
dealers_hand = []

#

# Testing code for step 1 
##card = playing_cards.deal_one_card()
##print(card)


# Player

# Deal first card
card = playing_cards.deal_one_card()

# Append it to the player_hand list
player_hand.append(card)
# Deal second card
card = playing_cards.deal_one_card()
# Append it to the player_hand list
player_hand.append(card)
#ADDING UP BOTH CARDS

# Display the player's hand to the screen using a simple print statement
print("Player's hand is ",  player_hand)



#Stage 3 - dealer

# Deal first card
card = playing_cards.deal_one_card()
# Append it to the player_hand list
dealers_hand.append(card)
# Deal second card
card = playing_cards.deal_one_card()
# Append it to the player_hand list
dealers_hand.append(card)
# Display the player's hand to the screen using a simple print statement
print(dealers_hand)

这是另一个文件，但任务说我不能修改它，我只是添加了它，使它更容易理解

deck = ['AH','2H','3H','4H','5H','6H','7H','8H','9H','TH','JH','QH','KH',
        'AD','2D','3D','4D','5D','6D','7D','8D','9D','TD','JD','QD','KD',
        'AS','2S','3S','4S','5S','6S','7S','8S','9S','TS','JS','QS','KS',
        'AC','2C','3C','4C','5C','6C','7C','8C','9C','TC','JC','QC','KC']

# Playing deck in use
playing_deck = []


# Function to determine whether there are any cards left in the
# deck of playing cards
# Parameters: No parameters
# Returns: True if the deck is empty, False otherwise
def is_empty_deck():

    # Check to see whether playing deck is empty
    return len(playing_deck) == 0


# Function to rebuild and shuffle the deck
# Parameters: No parameters
# Returns: Nothing is returned from the function.
def reset_deck():
    global playing_deck

    # Create new playing deck
    playing_deck = deck.copy()

    # Shuffle deck
    random.shuffle(playing_deck)


# Function to deal one card
# Parameters: No parameters
# Returns: A string (containing two characters) representing
# the card delt, i.e. '2H' meaning 2 of Hearts
def deal_one_card():

    # Check to see whether there are any cards left
    if is_empty_deck():

        # Rebuild and shuffle deck
        reset_deck()

    # Return a card (string of two characters)
    return playing_deck.pop(0)

Answer 1

dict对此有很大帮助：

def card(code):
    ref = {'C': 'Club', 'H': 'Heart', 'D': 'Diamond', 'S': 'Spade'}
    value = {'A': 'Ace', '2': 'Two', '3': 'Three', '4': 'Four', '5': 'Five',
             '6': 'Six', '7': 'Seven', '8': 'Eight', '9': 'Nine', 'T': 'Ten',
             'J': 'Jack', 'Q': 'Queen', 'K': 'King'}
    return value[code[0]] + ' of ' + ref[code[-1]]

测试：

[print(card(i)) for i in deck]

输出：

Ace of Hearts
Two of Hearts
Three of Hearts
Four of Hearts
Five of Hearts
Six of Hearts
Seven of Hearts
Eight of Hearts
... ...
Nine of Clubs
Ten of Clubs
Jack of Clubs
Queen of Clubs
King of Clubs

import inflect

deck = ['AH','2H','3H','4H','5H','6H','7H','8H','9H','TH','JH','QH','KH',
        'AD','2D','3D','4D','5D','6D','7D','8D','9D','TD','JD','QD','KD',
        'AS','2S','3S','4S','5S','6S','7S','8S','9S','TS','JS','QS','KS',
        'AC','2C','3C','4C','5C','6C','7C','8C','9C','TC','JC','QC','KC']

def card(code):
    ref = {'C': 'Clubs', 'H': 'Hearts', 'D': 'Diamonds', 'S': 'Spades',
           'A': 'Ace',  'T': 'Ten', 'J': 'Jack', 'Q': 'Queen', 'K': 'King'}
    if code[0] not in [str(i) for i in range(1, 10)]:
        return ref[code[0]] + ' of ' + ref[code[-1]]
    return inflect.engine().number_to_words(int(code[0])) + ' of ' + ref[code[-1]]

[print(card(i)) for i in deck]

Answer 2

您只需编写一个函数，将1c转换为俱乐部的1。您可以使用字典来执行套装的映射。

d = dict()
domain = ['C', 'H', 'D', 'S']
image = ['Club', 'Heart', 'Diamond', 'Spade']
for i in range(4):
    d[domain[i]] = image[i]

def process(x):
    return x[0] + ' of ' + d[x[1]]

print(process('1C'))