Spring支撑模板-401未经授权的错误

Question

我正在SpringBoot应用程序中使用SpringREST模板。

即使我正在传递凭据，我也总是收到未经授权的错误。

我可以通过ChromeREST Web Service Client访问此服务。

在SpringBoot中是否有访问REST模板的简化方法。

下面是到目前为止完成的导致401错误的代码片段

 private DetailsBean invokeDetailsRestService(UserParam userParam){
    ResponseEntity<DetailsBean> responseEntity = null;
    String url = "https://dev.com/app/identifyuser/";
    RestClientConfig restClientConfig =new RestClientConfig("user123","pass123");
    responseEntity= restClientConfig.postForEntity(url, userParam, DetailsBean.class);
    log.debug("User Details : {} ", responseEntity.getBody());
    return responseEntity.getBody();
}

public ClientHttpRequestFactory getRequestFactory(String userName,String password){
    CredentialsProvider credsProvider = new BasicCredentialsProvider();
    credsProvider.setCredentials( new AuthScope(null, -1), new UsernamePasswordCredentials(userName,password) );
    HttpClient httpClient = HttpClients.custom().setDefaultCredentialsProvider(credsProvider).build();
    return new HttpComponentsClientHttpRequestFactory(httpClient);
}

RestClientConfig类

  public RestClientConfig(String username, String password) {
    CredentialsProvider credsProvider = new BasicCredentialsProvider();
    credsProvider.setCredentials(
            new AuthScope(null, -1),
            new UsernamePasswordCredentials(username, password));
    HttpClient httpClient = HttpClients.custom().setDefaultCredentialsProvider(credsProvider).build();
    setRequestFactory(new HttpComponentsClientHttpRequestFactory(httpClient));
}

错误：

WARN c7af55b5-1cac-4db6-a202-202416c27ba4 
 12612 --- [apr-8082-exec-8] o.a.http.impl.auth.HttpAuthenticator    
: NEGOTIATE authentication error: 
No valid credentials provided (Mechanism level: 
No valid credentials provided (Mechanism level: 
Failed to find any Kerberos tgt))

Answer 1

我使用了Spring引导2.2.4。然后我下面的工作方式。

RestTemplate restTemplate = new RestTemplate();
restTemplate.getInterceptors().add(new BasicAuthenticationInterceptor(username, password));
RequestDto requestDto = new RequestDto();
// set parameter 
ResponseDto response = restTemplate.postForObject(URL, requestDto, ResponseDto.class);

或

RestTemplate restTemplate = new RestTemplate();
HttpHeaders headers = new HttpHeaders();
headers.setBasicAuth(username, password);
RequestDto requestDto = new RequestDto();
// set parameter 
HttpEntity<RequestDto> request = new HttpEntity<>(requestDto, headers);
ResponseDto response = restTemplate.postForObject(URL, request, ResponseDto.class);

Answer 2

我在尝试调用webservice时遇到了类似的问题，这解决了我的问题：

restTemplate.getInterceptors().add(new BasicAuthorizationInterceptor("userName", "password"));
restTemplate.postForObject('','',''');

像这样通过证书，应该可以解决问题。

Answer 3

使用以下代码修复了授权问题。。

凭据应通过以下代码传递给Spring REST模板：

   String userAndPass = "Test:Test123";

   HttpHeaders headers = new HttpHeaders();
    headers.setContentType(MediaType.APPLICATION_XML);
    headers.add("Authorization", "Basic " +  Base64Utility.encode(userAndPass.getBytes()));