如何在数组中只匹配一个用户名和密码

Question

$data = array(

array(
    'username' => '[e-mail]',
    'password' => '12345'
),
array(
    'username' => '[e-mail]',
    'password' => '8520'
),
array(
    'username' =>'[e-mail]',
    'password' => '123123'
)

）；

我的状况是这样的

我的任务是将一个用户名与一个密码匹配，但我出错了

$check_email = false;
               if(array_search($email,array_column($data,'username')) !== FALSE){
                   $check_email = true;
               }
               $check_pass = false;
               if(array_search($password,array_column($data,'password')) !== FALSE){
                   $check_pass = true;
               }
               if(!empty($check_email) && !empty($check_pass)){
                   echo "<h2>Email and Password matched</h2>";
               }
               else{
                   echo '<h2>Oh no email and password not matched.</h2>';

我正在使用array_column函数来匹配我条件。

Answer 1

您需要更新您的逻辑，该逻辑检查每个子数组中的用户名和密码是否相同。我做了快速逻辑，您应该应用到您的代码。

<?php 
$email = "[e-mail]";
$password = "12345";
$data = array(
    array(
        'username' => '[e-mail]',
        'password' => '12345'
    ),
    array(
        'username' => '[e-mail]',
        'password' => '8520'
    ),
    array(
        'username' =>'[e-mail]',
        'password' => '123123'
    )
    );
$hasSameMailAndPass = false;
foreach($data as $key => $value){
    if($value["username"] == $email and $value["password"] == $password){
        $hasSameMailAndPass = true;
    }
}
if($hasSameMailAndPass){
    echo "<h2>Email and Password matched</h2>";
} else {
    echo '<h2>Oh no email and password not matched.</h2>';
}
?>