用ngIF点击外部指令？

Question

如果click在具体的DOM元素之外，我使用下面的指令来检测和隐藏块:

import {
  Directive,
  ElementRef,
  Output,
  EventEmitter,
  HostListener
} from "@angular/core";

@Directive({
  selector: "[clickOutside]"
})
export class ClickOutsideDirective {
  constructor(private _elementRef: ElementRef) {}

  @Output()
  public clickOutside = new EventEmitter();

  @HostListener("document:click", ["$event.target"])
  public onClick(targetElement) {
    const clickedInside = this._elementRef.nativeElement.contains(
      targetElement
    );

    this.clickOutside.emit(clickedInside);
  }
}

我已将此指令应用于元素:

<div class="action" (click)="open()">Open</div>
<div
    class="search_content"
    *ngIf="_searchContentOpen"
    clickOutside
    (clickOutside)="clickOutside($event)"
  ></div>

部件代码为：

open(): void {
   this._searchContentOpen = !this._searchContentOpen;
}

问题是当我调用click时，我设置了< code >这个。_searchContentOpen设置为真/假。

视情况而定，我在应用指令的地方显示块。但是当ngIF工作时，指令也总是同步工作。所以结果块永远不会显示。

如何修复它？

Answer 1

以下是我的两个选择：

1）在触发器上使用event.stop传播（）

<div class="action" (click)="open(); $event.stopPropagation()">Open</div>

2） 仅在应用指令后处理点击

@Directive({
  selector: '[clickOutside]'
})
export class ClickOutsideDirective implements OnInit {
  @Output() clickOutside = new EventEmitter();

  captured = false;

  constructor(private elRef: ElementRef) { }

  @HostListener('document:click', ['$event.target'])
  onClick(target) {
    if (!this.captured) {
      return;
    }

    if (!this.elRef.nativeElement.contains(target)) {
      this.clickOutside.emit();
    };
  }

  ngOnInit() {
    fromEvent(document, 'click', { capture: true }).pipe(take(1))
      .subscribe(() => this.captured = true);

    /* or
    document.addEventListener('click', () => this.captured = true, { 
      capture: true,
      once: true
    });
    */
  }
}

Ng-run示例