从Curl POST请求中提取数据

Question

我正在使用curl发出一个POST请求，如下所示

curl -H 'Accept: application/json' \
-H 'Content-Type: application/json' \
-X POST \
-d '{ "name": "PhoneName", "description": "Phone Description!", "details": { "imeiNumber": "123456789123456", "phoneNumber": "9999999999"}}' \
-k \
http://test.domain.com/myTestServer/devices

但在servlet中,我无法获取任何数据。

public void devices(HttpServletRequest request, HttpServletResponse response) throws IOException {

    System.out.println("Got Request for devices");
    System.out.println("Request is : "+ request);
    System.out.println("Name : " + request.getParameter("name"));   //gives null
    System.out.println("description : " + request.getParameter("description")); //gives null
    Enumeration<String> paramNames = request.getParameterNames();   //Empty Enumeration
    while(paramNames.hasMoreElements()){
        String paramName = paramNames.nextElement();
        System.out.println(paramName + " : " + request.getParameter(paramName));

    }

}

有什么建议吗？还有一种在数据内部获取数据的更好方法，如“details”：{“imeinumber”：“123456789123456”，“phoneNumber”：“99999999999”}？

Answer 1

有什么建议吗？还有一种更好的方法可以在数据中获取数据，如“details”：{“imeinumber”：“123456789123456”，“phoneNumber”：“99999999999”}

对不起，我对curl没有任何想法，但我可以帮助您使用GSON库解析JSON字符串。只需将上面的JSON字符串封装在{...}中，并将其解析为Java对象，如下面的示例代码所示。示例代码：

class Details {
    private String name;
    private String description;
    private PhoneNumberDetails details;
    // getter & setter  
}


class PhoneNumberDetails{
    private String imeiNumber;
    private String phoneNumber;
    // getter & setter    
}

String json = "{ \"name\": \"PhoneName\", \"description\": \"Phone Description!\", \"details\": { \"imeiNumber\": \"123456789123456\", \"phoneNumber\": \"9999999999\"}}";
Details data = new Gson().fromJson(json, Details.class);
System.out.println(new GsonBuilder().setPrettyPrinting().create().toJson(data));

输出：

{
  "name": "PhoneName",
  "description": "Phone Description!",
  "details": {
    "imeiNumber": "123456789123456",
    "phoneNumber": "9999999999"
  }
}

Answer 2

-d'{“name”：“phoneName”,“description”：“phone description！”,“details”：{“imeinumber”：“123456789123456”,“phoneNumber”：“9999999999”}}'\

将输入json推送到POST请求负载中。并且不能简单地使用输入的json属性的名称来解组，因此可以得到

System.out.println("Name : " + request.getParameter("name"));   //gives null

这类语句的null值。

您需要从HttpServletRequest对象读取POST请求负载，然后使用json解析器解析它以获得属性值。

您可以像这样读取整个POST请求负载：

try {
    InputStream inputStream = request.getInputStream();
    if (inputStream != null) {
        bufferedReader = new BufferedReader(new InputStreamReader(inputStream));
        char[] charBuffer = new char[128];
        int bytesRead = -1;
        while ((bytesRead = bufferedReader.read(charBuffer)) > 0) {
            stringBuilder.append(charBuffer, 0, bytesRead);
        }
    } else {
        stringBuilder.append("");
    }
} catch (IOException ex) {
    throw ex;
} finally {
    if (bufferedReader != null) {
        try {
            bufferedReader.close();
        } catch (IOException ex) {
            throw ex;
        }
    }
}

body = stringBuilder.toString();

现在您应该在可变体中获得输入json。现在使用json解析器获取Attributes值，例如如下所示：

JsonParser parser = new JsonParser();
JsonObject obj = parser.parse(body).getAsJsonObject();
String name = obj.get("name").toString();