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问题:

失败:缺少必需的请求正文:public SpringFramework.HTTP.ResponseEntity…PostController

龚振
2023-03-14

我创建了基于Web的应用程序示例:Angular的前端和spring boot mer客户的后端)Angular URL:http://localhost:4200/spring boot URL:http://localhost:9020/(REST:http://localhost:9020/API/)

<h1>Angular Part </h1>

`export class Customer {
    id: number;
    firstname: number;
    lastname: Number;
    age: number;
    active: boolean;}`
import { Customer } from './customer';
    export class CustomerService {
      private baseUrl = http://localhost:9020/api';

      constructor(private http: HttpClient) { }

     getCustomer(id: number): Observable<Object> {
        return this.http.get(${this.baseUrl}+`/customers`+/${id});}

      createCustomer(customer: Customer): Observable<Object> {
        console.log("customer.lastname: "+customer.lastname);
        console.log("customer.firstname: "+customer.firstname);
        return this.http.post(${this.baseUrl} + `/create`, customer);
      }
      getCustomersList(): Observable<any> {
        return this.http.get(${this.baseUrl}+`/customers`);
      }
    }


    import { Component, OnInit } from '@angular/core';
    import { Customer } from '../customer';
    import { CustomerService } from '../customer.service';`

    @Component({
      selector: 'create-customer',
      templateUrl: './create-customer.component.html',
      styleUrls: ['./create-customer.component.css']
    })

    export class CreateCustomerComponent implements OnInit {
      customer: Customer = new Customer();
      submitted = false;
      constructor(private customerService: CustomerService) { }
      ngOnInit() {
      }

      newCustomer(): void {
        this.submitted = false;
        this.customer = new Customer();
      }

      save() {
        this.customerService.createCustomer(this.customer)
          .subscribe(data => {console.log(data);
            this.submitted = true;},error => console.log(error));
            this.customer = new Customer();}

      onSubmit() {   
        this.save();}}
@Entity
@Table(name = "customer")
public class Customer implements Serializable {

    private static final long serialVersionUID = -3009157732242241606L;

    @Id
    @GeneratedValue(strategy = GenerationType.AUTO)
    private long id;

    @Column(name = "last_Name")
    private String lastName;

    @Column(name = "first_Name")
    private String firstName;

    @Column(name = "age")
    private int age;

    @Column(name = "active")
    private boolean active = true;

    public Customer() {
    }

    public Customer(String firstName, String lastName, int age, boolean active) {
        this.firstName = firstName;
        this.lastName = lastName;
        this.age = age;
        this.active=active;
}

    public long getId() {
        return id;
    }

    public String getFirstName() {
        return firstName;
    }

    public void setFirstName(String firstName) {
        this.firstName = firstName;
    }

    public void setLastName(String lastName) {
        this.lastName = lastName;
    }

    public String getLastName() {
        return this.lastName;
    }

    public void setAge(int age) {
        this.age = age;
    }

    public int getAge() {
        return this.age;
    }

    public boolean isActive() {
        return active;
    }

    public void setActive(boolean active) {
        this.active = active;
    }
}

.

@CrossOrigin(origins = "http://localhost:4200")
@RestController
@RequestMapping("/api")
public class CustomerController {

  @Autowired
  CustomerRepository repository;


  @PostMapping(value = "/create")
  public ResponseEntity<Customer> postCustomer(@RequestBody Customer customer) {
    try {
      Customer _customer = repository.save(new Customer(customer.getFirstName(),customer.getLastName(),customer.getAge(),customer.isActive()));
      return new ResponseEntity<>(_customer, HttpStatus.CREATED);
    } catch (Exception e) {
      return new ResponseEntity<>(null, HttpStatus.EXPECTATION_FAILED);
    }
  }
}

.

CREATE TABLE customer(
       id INT NOT NULL AUTO_INCREMENT,
       firstname VARCHAR(20) NOT NULL,
       lastname VARCHAR(20) NOT NULL,
       PRIMARY KEY (id));

应用程序.属性:

>

  • server.port=9020
  • spring.datasource.url=jdbc:h2:file:./testdb
  • spring.datasource.username=h2 spring.datasource.password=password
  • spring.jpa.hibernate.ddl-auto=update
  • spring.jpa.show-sql=true`

    有效载荷{“id”:518,“lastName”:null,“firstName”:null,“age”:99,“active”:true}lastName和firstName应该是字符串值,因为我在这里输入字符串输入图像描述

    1:https://i.stack.imgur.com/2s8jh.png

  • 共有1个答案

    梅修贤
    2023-03-14

    在Entity类中,列名为“first_name”,但当您创建表时,它用“firstname”命名,下划线消失了。

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