在 javascript 数组中查找对象 [重复]

Question

所以这个问题以前被问过，但我的情况有点不同，因为我已经尝试了这个网站中建议的所有解决方案，我有一个多提及数组：

var array = [
{
    "dup":{ "lat":36.69507771893455,"lng":2.828052824475776 },
    "original":{ "lat":36.695076,"lng":2.8280580000000555}
},
{
    "dup":{ "lat":36.69507687630523,"lng":2.8280525056927672},
    "original":{ "lat":36.695076,"lng":2.8280580000000555}
},
{
    "dup":{ "lat":36.695076,"lng":2.8280523980529324},
    "original":{ "lat":36.695076,"lng":2.8280580000000555}
},
{
    "dup":{ "lat":36.69507512369477,"lng":2.8280525056927672},
    "original":{ "lat":36.695076,"lng":2.8280580000000555}
},
{
    "dup":{ "lat":36.69507428106545,"lng":2.828052824475776},
    "original":{ "lat":36.695076,"lng":2.8280580000000555}
},
{
    "dup":{ "lat":36.695073504493834,"lng":2.828053342151293},
    "original":{ "lat":36.695076,"lng":2.8280580000000555}
},
...
]

我还有另一个小数组：

var datax = {"lat":36.69507428106545,"lng":2.828052824475776}

我只想找到与这个“dup”在同一行的“original”。到目前为止，我尝试了查找、过滤和grep，但这些都没有解决我的问题。

我尝试过的代码：

var Cent = $.grep(array, function(e){ return e.dup== JSON.stringify(datax); });
contentString += " and "+Cent +"is the closer";

Answer 1

您仍然可以使用 Array.filter（） 来实现此目的：

var array = [{"dup":{"lat":36.69507771893455,"lng":2.828052824475776},"original":{"lat":36.695076,"lng":2.8280580000000555}},{"dup":{"lat":36.69507687630523,"lng":2.8280525056927672},"original":{"lat":36.695076,"lng":2.8280580000000555}},{"dup":{"lat":36.695076,"lng":2.8280523980529324},"original":{"lat":36.69507428106545,"lng":2.828052824475776}},{"dup":{"lat":36.69507512369477,"lng":2.8280525056927672},"original":{"lat":36.695076,"lng":2.8280580000000555}},{"dup":{"lat":36.69507428106545,"lng":2.828052824475776},"original":{"lat":36.695076,"lng":2.8280580000000555}},{"dup":{"lat":36.695073504493834,"lng":2.828053342151293},"original":{"lat":36.695076,"lng":2.8280580000000555}}];
var datax = {"lat":36.69507428106545,"lng":2.828052824475776}

var res = array.filter(item => item.original.lat === datax.lat && item.original.lng === datax.lng);
console.log(res);