如何使用Async/Await从用户获得输入，但要等到读取整个条件语句后才能解析？

Question

我创建了一个函数，该函数提示用户输入URL，然后验证输入的输入实际上是一个URL。问题是，当我从另一个函数调用这个函数时，我已经能够让它等待用户输入，但它在返回URL之前没有经过整个条件语句。

const readline = require('readline').createInterface({
   input: process.stdin,
   output: process.stdout,
});

// request url from user in command prompt
const requestSiteURL = () => {
  return new Promise((resolve, reject) => {
    readline.question('Please type url: ', async (url) => {
      if (validUrl.isUri(url)) {
        readline.close();
        resolve(url);
        // if user types no, then use base url
      } else if ('No' || 'no' || 'NO') {
        url = URL;
        resolve(url);
      } else {
        reject(
          console.log(
            'Please type in a valid URL or type "no" to use base url.'
          )
        );
        requestSiteURL();
      }
    });
  });
};

// grabs all urls from original link and returns array
const getURLS = async () => {
  let url = await requestSiteURL();
  url = deleteFowardSlash(url);
  try {
    const res = await axios.get(url);
    const data = res.data;
    const $ = cheerio.load(data);

    const urlQueue = [];

    // finds all absolute links and pushs to urlQueue array
    $("a[href^='http']").each((i, elem) => {
      let link = $(elem).attr('href');
      //checks to make sure link isnt any duplicate links in urlqueue array
      link = deleteFowardSlash(link);
      uniqueLinkChecker(link, urlQueue);
    });
    return urlQueue;
  } catch (err) {
    console.error(err);
    return response.status(400).send(err);
  }
};

Answer 1

我认为这是句法的问题。在这里，我将原来的行切换到正确使用Promise构造函数。许诺mdn

// request url from user in command prompt
const requestSiteURL = () => {
  return new Promise((resolve, reject) => {
    readline.question('Please type url: ', async (url) => {
      if (validUrl.isUri(url)) {
        readline.close();
        resolve(url);
        // if user types no, then use base url
      } else if (url.toLowerCase() === 'no') {
        url = URL;
        resolve(url);
      } else {
        console.log(
          'Please type in a valid URL or type "no" to use base url.'
        )
        requestSiteURL().then(resolve);
      }
    });
  });
};

编辑：添加异步/等待版本。基本上，我认为你不必拒绝。我编辑了上面的不拒绝以及。另外，我假设url是默认url（这与全局url命名空间冲突，仅供记录）

// request url from user in command prompt
const requestSiteURL = async function () {
  const url = await new Promise(resolve => {
    readline.question('Please type url: ', resolve)
  })
  if (validUrl.isUri(url)) {
    readline.close()
    return url
  } else if (url.toLowerCase() === 'no') {
    return URL
  } else {
    console.log('Please type in a valid URL or type "no" to use base url.')
    return requestSiteURL()
  }
}