如何在不中断 if 语句的情况下修复嵌套开关？

Question

我一直在尝试让开关语句在不嵌套的情况下工作，但它不起作用，因为它链接到我所做的if语句。

有人知道我如何在if语句仍然有效的情况下将boardType switch语句移到duration switch语句之外吗？非常感谢。

int duration = input.nextInt();

switch (duration) {
    default -> System.out.println("You have not entered a valid number of nights.");
    case 2, 7, 14 -> {
        System.out.print("How many guests are in your party? ");
        int guestAmount = input.nextInt();

        if (guestAmount >= 1 && guestAmount <= 10) {
            System.out.print("What type of board would you like (full, half, or self-catering)? ");
            String boardType = input.next();

            switch (boardType) {
                case "full", "half", "self-catering" ->
                        System.out.println("Valid details entered - booking may proceed");
                default -> System.out.println("Sorry, we do not cater that type of board.");
            }
        } else {
            System.out.println("Sorry, you are only allowed 1 to 10 guests.");

Answer 1

为了改进代码，可以将此逻辑提取到一个单独的方法中。

int duration = input.nextInt();
    
switch (duration) {
    default -> System.out.println("You have not entered a valid number of nights.");
    case 2, 7, 14 -> arrange(input);
}

public static void arrange(Scanner input) {
    System.out.print("How many guests are in your party? ");
    int guestAmount = input.nextInt();

    if (guestAmount >= 1 && guestAmount <= 10) {
        System.out.print("What type of board would you like (full, half, or self-catering)? ");
        String boardType = input.next();
    
        switch (boardType) {
            case "full", "half", "self-catering" -> System.out.println("Valid details entered - booking may proceed");
            default -> System.out.println("Sorry, we do not cater that type of board.");
        }
    } else {
        System.out.println("Sorry, you are only allowed 1 to 10 guests.");
    }
}

选择登机类型的逻辑也可以驻留在它自己的方法中。这样代码将更容易学习和理解。

public static void arrange(Scanner input) {
    System.out.print("How many guests are in your party? ");
    int guestAmount = input.nextInt();

    if (guestAmount >= 1 && guestAmount <= 10) {
        chooseBoardingType(input);
    } else {
        System.out.println("Sorry, you are only allowed 1 to 10 guests.");
    }
}

public static void chooseBoardingType(Scanner input) {
    System.out.print("What type of board would you like (full, half, or self-catering)? ");
    String boardType = input.next();

    switch (boardType) {
        case "full", "half", "self-catering" -> System.out.println("Valid details entered - booking may proceed");
        default -> System.out.println("Sorry, we do not cater that type of board.");
    }
}

Answer 2

您也可以在没有开关语句的情况下做到这一点。如果还有的话，嵌套将很容易实现。