Java-在Int arrayList上循环并求和所有数字

Question

早上好！

我试图循环一个int arrayList并计算所有的数字：

String strEthnicity = "df -i\n" +
        "Filesystem                    Inodes  IUsed    IFree IUse% Mounted on\n" +
        "/dev/mapper/vg0-rootvol       719488  42967   676521    6% /\n" +
        "devtmpfs                     4093600    436  4093164    1% /dev\n" +
        "tmpfs                        4096453      1  4096452    1% /dev/shm\n" +
        "tmpfs                        4096453   1384  4095069    1% /run\n" +
        "tmpfs                        4096453     16  4096437    1% /sys/fs/cgroup\n" +
        "/dev/sda1                      32768    351    32417    2% /boot\n" +
        "/dev/mapper/vg0-optvol        327680  19465   308215    6% /opt\n" +
        "/dev/mapper/vg0-homevol       131072    322   130750    1% /home\n" +
        "/dev/mapper/vg0-tmpvol        131072    166   130906    1% /tmp\n" +
        "/dev/mapper/vg0-varvol        327680   4486   323194    2% /var\n" +
        "/dev/mapper/vg0-logvol        131072    163   130909    1% /var/log\n" +
        "/dev/mapper/vg0-auditvol      327680     34   327646    1% /var/log/audit\n" +
        "/dev/mapper/vg1-optSPvol    32768000 156936 32611064    1% /opt/SP\n" +
        "/dev/mapper/vg0-varcrashvol  1048576     11  1048565    1% /var/crash\n" +
        "tmpfs                        4096453      1  4096452    1% /run/user/10603\n" +
        "[1;31mvg1108yr:resolve:[0m/opt/SP/resolve \$"

String strRegex = "(\\d+)\\s+(\\d+\\s+(\\d+)(?=\\s+\\d+\\%))"
Pattern pattern = Pattern.compile(strRegex);
Matcher matcher = pattern.matcher(strEthnicity);
while (matcher.find()) {


    String [] stringArray = matcher.group().split(" ")
    
    Integer[] numbers = new Integer[stringArray.length];
    for(int i = 0;i < stringArray.length;i++)
    {
        try
        {
            numbers[i] = Integer.parseInt(stringArray[i]);
        }
        catch (NumberFormatException nfe)
        {
            numbers[i] = null
        }
    }
    System.out.println(numbers[0])
}

719488
4093600
4096453
4096453
4096453
32768
327680
131072
131072
327680
131072
327680
32768000
1048576
4096453

谢谢。

Answer 1

只需将notNULL单元格求和：

int sum =0;

for(int i = 0;i < stringArray.length;i++)
    {
        try
        {
            numbers[i] = Integer.parseInt(stringArray[i]);
        }
        catch (NumberFormatException nfe)
        {
            numbers[i] = null
        }
        if(numbers[i]!=null) sum+=numbers[i];
    }
System.out.println(sum);