在空格上分割，某些字符之间除外

Question

我正在解析包含以下行的文件

类型（“书”）标题（“金苹果”）页面（10-35 70 200-234）评论（“好书”）

我想将其拆分为单独的字段。

在我的示例中，有四个字段：类型，标题，页面和注释。

分割后的预期结果是

['type（“ book”）'，'title（“ golden apples”）'，'pages（10-35 70 200-234）'，'comments（“好书”）]

显然，简单的字符串拆分将不起作用，因为它将仅在每个空格处拆分。我想分割空格，但保留括号和引号之间的所有内容。

我该如何拆分？

Answer 1

这个正则表达式应该为您工作 \s+(?=[^()]*(?:\(|$))

result = re.split(r"\s+(?=[^()]*(?:\(|$))", subject)

说明

r"""
\s             # Match a single character that is a “whitespace character” (spaces, tabs, and line breaks)
   +              # Between one and unlimited times, as many times as possible, giving back as needed (greedy)
(?=            # Assert that the regex below can be matched, starting at this position (positive lookahead)
   [^()]          # Match a single character NOT present in the list “()”
      *              # Between zero and unlimited times, as many times as possible, giving back as needed (greedy)
   (?:              # Match the regular expression below
                     # Match either the regular expression below (attempting the next alternative only if this one fails)
         \(             # Match the character “(” literally
      |              # Or match regular expression number 2 below (the entire group fails if this one fails to match)
         $              # Assert position at the end of a line (at the end of the string or before a line break character)
   )
)
"""