如何将mysqli结果转换为JSON？

Question

我有一个mysqli查询，我需要将其格式化为移动应用程序的JSON。

我已经设法为查询结果生成一个XML文档，但是我正在寻找更轻量的东西。（有关我当前的XML代码，请参见下文）

$mysql = new mysqli(DB_SERVER,DB_USER,DB_PASSWORD,DB_NAME) or die('There was a problem connecting to the database');

$stmt = $mysql->prepare('SELECT DISTINCT title FROM sections ORDER BY title ASC');
$stmt->execute();
$stmt->bind_result($title);

// create xml format
$doc = new DomDocument('1.0');

// create root node
$root = $doc->createElement('xml');
$root = $doc->appendChild($root);

// add node for each row
while($row = $stmt->fetch()) :

    $occ = $doc->createElement('data');  
    $occ = $root->appendChild($occ);

    $child = $doc->createElement('section');  
    $child = $occ->appendChild($child);  
    $value = $doc->createTextNode($title);  
    $value = $child->appendChild($value);

endwhile;

$xml_string = $doc->saveXML();

header('Content-Type: application/xml; charset=ISO-8859-1');

// output xml jQuery ready

echo $xml_string;

Answer 1

$mysqli = new mysqli('localhost','user','password','myDatabaseName');
$myArray = array();
if ($result = $mysqli->query("SELECT * FROM phase1")) {

    while($row = $result->fetch_array(MYSQLI_ASSOC)) {
            $myArray[] = $row;
    }
    echo json_encode($myArray);
}

$result->close();
$mysqli->close();

1. $row = $result->fetch_array(MYSQLI_ASSOC)
2. $myArray[] = $row

这样的输出：

[
    {"id":"31","name":"pruduct_name1","price":"98"},
    {"id":"30","name":"pruduct_name2","price":"23"}
]

如果您想要其他样式，可以尝试以下方法：

1. $row = $result->fetch_row()
2. $myArray[] = $row

输出将是这样的：

[
    ["31","pruduct_name1","98"],
    ["30","pruduct_name2","23"]
]