python parse http响应（字符串）

Question

我正在使用python
2.7，我想解析已经从文本文件中提取的字符串HTTP响应字段。最简单的方法是什么？我可以使用BaseHTTPServer解析请求，但无法为响应找到内容。

我的回复非常标准，并采用以下格式

HTTP/1.1 200 OK
Date: Thu, Jul  3 15:27:54 2014
Content-Type: text/xml; charset="utf-8"
Connection: close
Content-Length: 626

提前致谢，

Answer 1

您可能会发现这很有用，请记住HTTPResponse并非旨在“由用户直接实例化”。

还要注意，响应字符串中的content-
length标头可能不再有效（取决于您获取这些响应的方式），这仅意味着对HTTPResponse.read（）的调用需要具有大于内容的值为了得到一切。

在python 2中，可以这种方式运行。

from httplib import HTTPResponse
from StringIO import StringIO

http_response_str = """HTTP/1.1 200 OK
Date: Thu, Jul  3 15:27:54 2014
Content-Type: text/xml; charset="utf-8"
Connection: close
Content-Length: 626"""

class FakeSocket():
    def __init__(self, response_str):
        self._file = StringIO(response_str)
    def makefile(self, *args, **kwargs):
        return self._file

source = FakeSocket(http_response_str)
response = HTTPResponse(source)
response.begin()
print "status:", response.status
print "single header:", response.getheader('Content-Type')
print "content:", response.read(len(http_response_str)) # the len here will give a 'big enough' value to read the whole content

在python
3中，HTTPResponse从中导入http.client，并且要解析的响应需要进行字节编码。根据从何处获取数据，可能已经完成或需要显式调用

from http.client import HTTPResponse
from io import BytesIO

http_response_str = """HTTP/1.1 200 OK
Date: Thu, Jul  3 15:27:54 2014
Content-Type: text/xml; charset="utf-8"
Connection: close
Content-Length: 626

teststring"""

http_response_bytes = http_response_str.encode()

class FakeSocket():
    def __init__(self, response_bytes):
        self._file = BytesIO(response_bytes)
    def makefile(self, *args, **kwargs):
        return self._file

source = FakeSocket(http_response_bytes)
response = HTTPResponse(source)
response.begin()
print( "status:", response.status)
# status: 200
print( "single header:", response.getheader('Content-Type'))
# single header: text/xml; charset="utf-8"
print( "content:", response.read(len(http_response_str)))
# content: b'teststring'