学习Python的艰辛方法练习35帮助

Question

由于某种原因，当游戏到达金牌室时，它将无法正常工作。当我输入任何数字时，我会收到死亡消息“男人，学会键入数字”

谢谢

from sys import exit

def gold_room():
    print 'this room is full of gold, how much do you take?'

    next = raw_input('> ')
    if '0' in next or '1' in next:
        how_much = int(next)
    else:
        dead('man, learn how to type a number')


    if how_much < 50:
        print 'nice! your not too greedy. you win!'
        exit(0)
    else:
        dead('you greedy bastard!')


def bear_room():
    print 'there is a bear here.'
    print 'the bear has a bunch of honey'
    print 'the fat bear is in fromt of another door'
    print 'how are you going to move the bear?'
    bear_moved = False


    while True:
        next = raw_input('> ')

        if next == 'take honey':
            dead('the bear looks at you then pimp slaps you in the face')
        elif next == 'taunt bear' and not bear_moved:
            print 'the bear has moved from the door now. you can go through.'
            bear_moved = True
        elif next == 'taunt bear' and bear_moved:
            dead('the bear gets pissed off and chews your crotch off')
        elif next == 'open door' and bear_moved:
            gold_room()
        else:
            print 'i have no idea what that means.'


def bolofumps_room():
    print 'here you see the great evil bolofump'
    print 'he, it whatever stares at you and you go insane'
    print 'do you flee for your life or eat your head?'

    next = raw_input('> ')
    if 'flee' in next:
        start()
    elif 'head' in next:
        dead('well, that was tasty!')
    else:
        bolofumps_room()

def dead(why):
    print why, 'good job!'
    exit(0)


def start():
    print 'you are in a dark room'
    print 'there is a door to your left and right'
    print 'which one do you take?'

    next = raw_input('> ')

    if next == 'left':
        bear_room()
    elif next == 'right':
        bolofumps_room()
    else:
        dead('you stumble around the room until you starve to death')


start()

编辑：键入一个有效，但2不起作用

Answer 1

您在gold_room以下位置执行此操作：

next = raw_input('> ')
if '0' in next or '1' in next:
    how_much = int(next)
else:
    dead('man, learn how to type a number')

它只检查是否为'0' in next or '1' in next，所以‘2’不起作用并不奇怪，对吗？

您想要的就是这些路线

next = raw_input('> ')
try:
    how_much = int(next)
except ValueError:
    dead('man, learn how to type a number')

也可以无例外地做到这一点，但是请记住，避免像例外一样重要和根本的事情是一个非常糟糕的主意。我希望这本书至少在以后能使这一点变得清楚。

无论如何，所以我们知道那只int接受数字，因此我们只检查一下：

if next.isdigit():
    how_much = int(next)