用户输入以重复Java程序

Question

我正在编写一个简单的猜谜游戏程序，用户将输入一个数字来尝试猜测一个随机生成的数字。

如果他们的号码正确，我想给他们选择再次玩的机会。

这是我的代码：

public class GuessingGame {
    private Random num = new Random();       
    private int answer = num.nextInt(10);   
    private int guess;  
    private String playAgain;

    public void inputGuess(){
        System.out.println("Enter a number between 1 and 10 as your first guess: ");
        Scanner input = new Scanner(System.in);
        guess = input.nextInt(); 
        do{
        if (guess < 1 || guess > 10){
            System.out.println("That is not a valid entry. Please try again: ");
            guess = input.nextInt();
        }else if (guess > answer){
            System.out.println("Too high, Try Again: ");
            guess = input.nextInt();
        }else if (guess < answer){
            System.out.println("Too low, Try Again: ");
            guess = input.nextInt();
        }

        }while (guess != answer);

        System.out.println("Congratulations, You guessed the number!");
        System.out.println("Would you like to play again? Enter Y to play or any other key to quit: ");
        playAgain = input.nextLine();
        if(playAgain == "Y" || playAgain == "y"){
            System.out.println("Enter a number between 1 and 10 as your first guess: ");
            guess = input.nextInt(); 
        }

    }
}

游戏进行完毕，但是提示用户再次玩游戏时，什么都没有发生？

有什么建议？

Answer 1

这是完整的代码，完全可以使用并经过测试。

    public static void main(String[] args)
    {
    String playAgain = "";
    Scanner scan = new Scanner(System.in);

    do
    {
        ClassName.inputGuess();
        System.out.println("Would you like to play again? Enter Y to play or any other key to quit: ");
        playAgain = scan.nextLine();
    }
    while(playAgain.equalsIgnoreCase("Y"));
    System.out.println("Thanks for playing!");
}

public void inputGuess()
{
    Random num = new Random();
    int answer = num.nextInt(10)+1;
    Scanner input = new Scanner(System.in);
    int guess;

    System.out.println("Enter a number between 1 and 10 as your first guess: ");
    guess = input.nextInt();

    do
    {
        if (guess < 1 || guess > 10)
        {
            System.out.println("That is not a valid entry. Please try again: ");
            guess = input.nextInt();
        }
        else 
            if (guess > answer)
            {
                System.out.println("Too high, Try Again: ");
                guess = input.nextInt();
            }
            else 
                if (guess < answer)
                {
                    System.out.println("Too low, Try Again: ");
                    guess = input.nextInt();
                }
        input.nextLine();

    }
    while (guess != answer);

    System.out.println("Congratulations, You guessed the number!");
}