我是REST API的新手。我想使用REST
API将用户选择的文件上传到用户提供的路径(远程或本地路径)。我的html文件具有1个文本框和1个文件选择器。用户将在文本框中输入FilePath(本地或远程计算机文件夹位置)。请提出如何解决此问题的建议。
这是我的代码:
FileUpload.html ::
<body>
<form action="rest/file/upload" method="post" enctype="multipart/form-data">
<p>
Select a file : <input type="file" name="file" size="45" />
</p>
<p>Target Upload Path : <input type="text" name="path" /></p>
<input type="submit" value="Upload It" />
</form>
</body>
UploadFileService.java
@Path("/file")
public class UploadFileService {
@POST
@Path("/upload")
@Consumes(MediaType.MULTIPART_FORM_DATA)
public Response uploadFile(
@FormDataParam("file") InputStream uploadedInputStream,
@FormDataParam("file") FormDataContentDisposition fileDetail,
@FormParam("path") String path) {
/*String uploadedFileLocation = "d://uploaded/" + fileDetail.getFileName();*/
/*String uploadedFileLocation = //10.217.14.88/Installables/uploaded/" + fileDetail.getFileName();*/
String uploadedFileLocation = path
+ fileDetail.getFileName();
// save it
writeToFile(uploadedInputStream, uploadedFileLocation);
String output = "File uploaded to : " + uploadedFileLocation;
return Response.status(200).entity(output).build();
}
// save uploaded file to new location
private void writeToFile(InputStream uploadedInputStream,
String uploadedFileLocation) {
try {
OutputStream out = new FileOutputStream(new File(
uploadedFileLocation));
int read = 0;
byte[] bytes = new byte[1024];
out = new FileOutputStream(new File(uploadedFileLocation));
while ((read = uploadedInputStream.read(bytes)) != -1) {
out.write(bytes, 0, read);
}
out.flush();
out.close();
} catch (IOException e) {
e.printStackTrace();
}
}
}
Web.xml
<display-name>JAXRSFileUploadJerseyExample</display-name>
<servlet>
<servlet-name>jersey-serlvet</servlet-name>
<servlet-class>com.sun.jersey.spi.container.servlet.ServletContainer</servlet-class>
<init-param>
<param-name>com.sun.jersey.config.property.packages</param-name>
<param-value>com.mkyong.rest</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>jersey-serlvet</servlet-name>
<url-pattern>/rest/*</url-pattern>
</servlet-mapping>
例外:
HTTP Status 500 - com.sun.jersey.api.container.ContainerException: Exception obtaining parameters
type Exception report
message com.sun.jersey.api.container.ContainerException: Exception obtaining parameters
description The server encountered an internal error that prevented it from fulfilling this request.
exception
javax.servlet.ServletException: com.sun.jersey.api.container.ContainerException: Exception obtaining parameters
com.sun.jersey.spi.container.servlet.WebComponent.service(WebComponent.java:425)
com.sun.jersey.spi.container.servlet.ServletContainer.service(ServletContainer.java:537)
com.sun.jersey.spi.container.servlet.ServletContainer.service(ServletContainer.java:699)
javax.servlet.http.HttpServlet.service(HttpServlet.java:728)
root cause
com.sun.jersey.api.container.ContainerException: Exception obtaining parameters
com.sun.jersey.server.impl.inject.InjectableValuesProvider.getInjectableValues(InjectableValuesProvider.java:54)
com.sun.jersey.multipart.impl.FormDataMultiPartDispatchProvider$FormDataInjectableValuesProvider.getInjectableValues(FormDataMultiPartDispatchProvider.java:125)
com.sun.jersey.server.impl.model.method.dispatch.AbstractResourceMethodDispatchProvider$EntityParamInInvoker.getParams(AbstractResourceMethodDispatchProvider.java:153)
com.sun.jersey.server.impl.model.method.dispatch.AbstractResourceMethodDispatchProvider$ResponseOutInvoker._dispatch(AbstractResourceMethodDispatchProvider.java:203)
com.sun.jersey.server.impl.model.method.dispatch.ResourceJavaMethodDispatcher.dispatch(ResourceJavaMethodDispatcher.java:75)
com.sun.jersey.server.impl.uri.rules.HttpMethodRule.accept(HttpMethodRule.java:288)
com.sun.jersey.server.impl.uri.rules.RightHandPathRule.accept(RightHandPathRule.java:147)
com.sun.jersey.server.impl.uri.rules.ResourceClassRule.accept(ResourceClassRule.java:108)
com.sun.jersey.server.impl.uri.rules.RightHandPathRule.accept(RightHandPathRule.java:147)
com.sun.jersey.server.impl.uri.rules.RootResourceClassesRule.accept(RootResourceClassesRule.java:84)
com.sun.jersey.server.impl.application.WebApplicationImpl._handleRequest(WebApplicationImpl.java:1469)
com.sun.jersey.server.impl.application.WebApplicationImpl._handleRequest(WebApplicationImpl.java:1400)
com.sun.jersey.server.impl.application.WebApplicationImpl.handleRequest(WebApplicationImpl.java:1349)
com.sun.jersey.server.impl.application.WebApplicationImpl.handleRequest(WebApplicationImpl.java:1339)
com.sun.jersey.spi.container.servlet.WebComponent.service(WebComponent.java:416)
com.sun.jersey.spi.container.servlet.ServletContainer.service(ServletContainer.java:537)
com.sun.jersey.spi.container.servlet.ServletContainer.service(ServletContainer.java:699)
javax.servlet.http.HttpServlet.service(HttpServlet.java:728)
root cause
java.lang.IllegalStateException: The @FormParam is utilized when the content type of the request entity is not application/x-www-form-urlencoded
com.sun.jersey.server.impl.model.parameter.FormParamInjectableProvider$FormParamInjectable.getValue(FormParamInjectableProvider.java:81)
com.sun.jersey.server.impl.inject.InjectableValuesProvider.getInjectableValues(InjectableValuesProvider.java:46)
com.sun.jersey.multipart.impl.FormDataMultiPartDispatchProvider$FormDataInjectableValuesProvider.getInjectableValues(FormDataMultiPartDispatchProvider.java:125)
com.sun.jersey.server.impl.model.method.dispatch.AbstractResourceMethodDispatchProvider$EntityParamInInvoker.getParams(AbstractResourceMethodDispatchProvider.java:153)
com.sun.jersey.server.impl.model.method.dispatch.AbstractResourceMethodDispatchProvider$ResponseOutInvoker._dispatch(AbstractResourceMethodDispatchProvider.java:203)
com.sun.jersey.server.impl.model.method.dispatch.ResourceJavaMethodDispatcher.dispatch(ResourceJavaMethodDispatcher.java:75)
com.sun.jersey.server.impl.uri.rules.HttpMethodRule.accept(HttpMethodRule.java:288)
com.sun.jersey.server.impl.uri.rules.RightHandPathRule.accept(RightHandPathRule.java:147)
com.sun.jersey.server.impl.uri.rules.ResourceClassRule.accept(ResourceClassRule.java:108)
com.sun.jersey.server.impl.uri.rules.RightHandPathRule.accept(RightHandPathRule.java:147)
com.sun.jersey.server.impl.uri.rules.RootResourceClassesRule.accept(RootResourceClassesRule.java:84)
com.sun.jersey.server.impl.application.WebApplicationImpl._handleRequest(WebApplicationImpl.java:1469)
com.sun.jersey.server.impl.application.WebApplicationImpl._handleRequest(WebApplicationImpl.java:1400)
com.sun.jersey.server.impl.application.WebApplicationImpl.handleRequest(WebApplicationImpl.java:1349)
com.sun.jersey.server.impl.application.WebApplicationImpl.handleRequest(WebApplicationImpl.java:1339)
com.sun.jersey.spi.container.servlet.WebComponent.service(WebComponent.java:416)
com.sun.jersey.spi.container.servlet.ServletContainer.service(ServletContainer.java:537)
com.sun.jersey.spi.container.servlet.ServletContainer.service(ServletContainer.java:699)
javax.servlet.http.HttpServlet.service(HttpServlet.java:728)
我在下面的类中更新了方法的签名,并且它的工作正常。而不是@FormParam
使用@FormDataParam("path")
String路径,它解决了我的问题。下面是更新的代码:
import java.io.File;
import java.io.FileOutputStream;
import java.io.IOException;
import java.io.InputStream;
import java.io.OutputStream;
import javax.ws.rs.Consumes;
import javax.ws.rs.FormParam;
import javax.ws.rs.POST;
import javax.ws.rs.Path;
import javax.ws.rs.core.MediaType;
import javax.ws.rs.core.Response;
import com.sun.jersey.core.header.FormDataContentDisposition;
import com.sun.jersey.multipart.FormDataParam;
@Path("/file")
public class UploadFileService {
@POST
@Path("/upload")
@Consumes(MediaType.MULTIPART_FORM_DATA)
public Response uploadFile(
@FormDataParam("file") InputStream uploadedInputStream,
@FormDataParam("file") FormDataContentDisposition fileDetail,
@FormDataParam("path") String path) {
// Path format //10.217.14.97/Installables/uploaded/
System.out.println("path::"+path);
String uploadedFileLocation = path
+ fileDetail.getFileName();
// save it
writeToFile(uploadedInputStream, uploadedFileLocation);
String output = "File uploaded to : " + uploadedFileLocation;
return Response.status(200).entity(output).build();
}
// save uploaded file to new location
private void writeToFile(InputStream uploadedInputStream,
String uploadedFileLocation) {
try {
OutputStream out = new FileOutputStream(new File(
uploadedFileLocation));
int read = 0;
byte[] bytes = new byte[1024];
out = new FileOutputStream(new File(uploadedFileLocation));
while ((read = uploadedInputStream.read(bytes)) != -1) {
out.write(bytes, 0, read);
}
out.flush();
out.close();
} catch (IOException e) {
e.printStackTrace();
}
}
}
我使用已签名的URL从使用Air的移动设备上传blob。 我有两个问题: 使用签名 URL 上传 Blob 时,我假设我不需要按照文档中所述包含所有标头。我是否认为我只需要对URL执行请求,并将编码到正文中的文件包含在正文中,设置为? http://msdn . Microsoft . com/en-us/library/windows azure/DD 179451 . aspx (Upload
我是REST API的新手。我想上传用户选择的文件到用户提供的路径(远程或本地路径)使用REST API。我的html文件有一个文本框和一个文件选择器。用户将在文本框中输入文件路径(本地或远程计算机文件夹位置)。请建议如何解决这个问题。 下面是我的代码: 例外情况:
问题内容: 我正在创建用于发送邮件的邮件页面。我需要在发送前附加一些文件。我如何使用AJAX做到这一点?最初,我需要将这些文件存储在服务器中,然后必须发送邮件。通过单个发送按钮即可完成这些操作。 问题答案: 检查以下问题: JavaScript文件上传 如何为我的Web应用程序上传类似Gmail的文件? 什么是最好的多文件JavaScript / Flash文件上传器?
问题内容: 谁能让我知道如何使用Java代码使用Selenium上传文件? 当我单击应用程序中的按钮时,它将在新窗口中打开,可以用来选择上传文件。Silverlight(C#)开发的浏览按钮。 问题答案: 首先确保输入元素可见 正如Mark Collin在此处的讨论中所述: 不要单击浏览按钮,它会触发操作系统级别的对话框并有效地停止测试。 相反,你可以使用: myUploadElement是该元素
谁能让我知道如何通过Java代码使用Selenium上传文件? 当我点击应用程序中的按钮时,它会在新窗口中打开,我可以用它来选择上传文件。Silverlight(C#)开发的浏览按钮。
我正在尝试使用多部分实体方法上传文件。但它失败,错误说{“错误”:“文件参数值'无'无效”} 我的代码是: File File = new File(" C:/Users/SST-06/Desktop/new . txt "); 我的实体文件包含所有提到的参数。 -hkYO-pblk 0 uqlxjtvklrbkosxz 7 mye-8 wbvbvanx Content-Disposition:f