在Java中引发异常后继续执行

Question

我正在尝试引发异常（不使用try
catch块），并且程序在引发异常后立即完成。有没有一种方法可以在我引发异常之后继续执行程序？我抛出了在另一个类中定义的InvalidEmployeeTypeException，但是我希望程序在抛出该异常后继续执行。

    private void getData() throws InvalidEmployeeTypeException{

    System.out.println("Enter filename: ");
    Scanner prompt = new Scanner(System.in);

    inp = prompt.nextLine();

    File inFile = new File(inp);
    try {
        input = new Scanner(inFile);
    } catch (FileNotFoundException ex) {
        ex.printStackTrace();
        System.exit(1);
    }

    String type, name;
    int year, salary, hours;
    double wage;
    Employee e = null;


    while(input.hasNext()) {
        try{
        type = input.next();
        name = input.next();
        year = input.nextInt();

        if (type.equalsIgnoreCase("manager") || type.equalsIgnoreCase("staff")) {
            salary = input.nextInt();
            if (type.equalsIgnoreCase("manager")) {
                e = new Manager(name, year, salary);
            }
            else {
                e = new Staff(name, year, salary);
            }
        }
        else if (type.equalsIgnoreCase("fulltime") || type.equalsIgnoreCase("parttime")) {
            hours = input.nextInt();
            wage = input.nextDouble();
            if (type.equalsIgnoreCase("fulltime")) {
                e = new FullTime(name, year, hours, wage);
            }
            else {
                e = new PartTime(name, year, hours, wage);
            }
        }
        else {


            throw new InvalidEmployeeTypeException();
            input.nextLine();

            continue;

        }
        } catch(InputMismatchException ex)
          {
            System.out.println("** Error: Invalid input **");

            input.nextLine();

            continue;

          }
          //catch(InvalidEmployeeTypeException ex)
          //{

          //}
        employees.add(e);
    }


}

Answer 1

试试这个：

try
{
    throw new InvalidEmployeeTypeException();
    input.nextLine();
}
catch(InvalidEmployeeTypeException ex)
{
      //do error handling
}

continue;