Swift POST请求不起作用

Question

我正在尝试向Swift发出发布请求。我的目标是将accesstoken facebook发布到服务器，但不起作用。这是代码：

let myUrlfb = NSURL(string: "MyApiServer");

let requestfb = NSMutableURLRequest(URL:myUrlfb!);

requestfb.HTTPMethod = "POST";// Compose a query string


//We make the post string
let postStringfb = FBSDKAccessToken.currentAccessToken().tokenString

requestfb.HTTPBody = postStringfb.dataUsingEncoding(NSUTF8StringEncoding);

let task = NSURLSession.sharedSession().dataTaskWithRequest(requestfb) {
                    data, response, error in

    if error != nil
    {
        print("error=\(error)")
        return

    }

答案如下：

{"statusCode":400,"error":"Bad Request","message":"child \"access_token\" fails because [access_token is required]","validation":{"source":"payload","keys":["access_token"]}})

Answer 1

通过这种方式，您可以使用POST Web服务：

func webApi() {
            let request = NSMutableURLRequest(URL: NSURL(string: "your url")!)
                    request.HTTPMethod = "POST"

            var string = "access_token="
            var postString =       string.stringByAppendingString(FBSDKAccessToken.currentAccessToken().tokenString)
                request.HTTPBody = postString.dataUsingEncoding(NSUTF8StringEncoding)
                let task = NSURLSession.sharedSession().dataTaskWithRequest(request) { data, response, error in
                    guard error == nil && data != nil else {                                                          // check for fundamental networking error
                        print("error=\(error)")
                        return
                    }

                    if let httpStatus = response as? NSHTTPURLResponse where httpStatus.statusCode != 200 {           // check for http errors
                        print("statusCode should be 200, but is \(httpStatus.statusCode)")
                        print("response = \(response)")
                    }

                    let responseString = NSString(data: data!, encoding: NSUTF8StringEncoding)
                    print("responseString = \(responseString)")
                }
                task.resume()
            }

    }//End of webapi function