如何在Android中的原始文件夹中引用文件

Question

我只想创建一个像这样的File对象

File myImageFile = new File ("image1") ;

但是它给了我 FileNotFoundException的 例外我
如何在我的原始文件夹中引用一个文件

编辑： 其实我想做这样的事情

MultipartEntity multipartEntity= new MultipartEntity(HttpMultipartMode.BROWSER_COMPATIBLE); multipartEntity.addPart("uploaded", new FileBody(new File("myimage")));

Answer 1

这是2个功能。一种是从RAW读取的，另一种是从资产读取的

/**
 * Method to read in a text file placed in the res/raw directory of the
 * application. The method reads in all lines of the file sequentially.
 */

public static void readRaw(Context ctx,int res_id) {

    InputStream is = ctx.getResources().openRawResource(res_id);
    InputStreamReader isr = new InputStreamReader(is);
    BufferedReader br = new BufferedReader(isr, 8192); // 2nd arg is buffer
                                                        // size

    // More efficient (less readable) implementation of above is the
    // composite expression
    /*
     * BufferedReader br = new BufferedReader(new InputStreamReader(
     * this.getResources().openRawResource(R.raw.textfile)), 8192);
     */

    try {
        String test;
        while (true) {
            test = br.readLine();
            // readLine() returns null if no more lines in the file
            if (test == null)
                break;
        }
        isr.close();
        is.close();
        br.close();
    } catch (IOException e) {
        e.printStackTrace();
    }

}

并从资产文件夹

/**
 * Read a file from assets
 * 
 * @return the string from assets
 */

public static String getQuestions(Context ctx,String file_name) {

    AssetManager assetManager = ctx.getAssets();
    ByteArrayOutputStream outputStream = null;
    InputStream inputStream = null;
    try {
        inputStream = assetManager.open(file_name);
        outputStream = new ByteArrayOutputStream();
        byte buf[] = new byte[1024];
        int len;
        try {
            while ((len = inputStream.read(buf)) != -1) {
                outputStream.write(buf, 0, len);
            }
            outputStream.close();
            inputStream.close();
        } catch (IOException e) {
        }
    } catch (IOException e) {
    }
    return outputStream.toString();

}