在playframework中上传多个文件

Question

我无法正常上传多个文件。当我选择x个文件时，它成功完成，但是第一个文件被上传了x次，而其他文件则根本没有被上传。有人能指出我做错了吗？

形成：

#{form @Projects.uploadPictures(project.id), enctype:'multipart/form-data'}

<p>
    <label>&{'title'}</label>
    <input type="text" name="title"/>
    <strong>(&{'addPicture.chooseTitle'})</strong>
</p>
<p>
    <label>&{'Pictures'}</label>
    <input type="file" multiple name="files" id="files"/>
</p>
<p>
    <input type="submit" value="&{'publish'}" />
</p>

#{/form}

处理文件：

public static void uploadPictures(long id, String title, List<Blob> files) {
    String error = "";        
    if(files != null && !title.trim().equals("")) {
        Project project = Project.findById(id);
        // Save uploaded files
        Picture picture;

        for(int i = 0; i<files.size(); i++) {
            if(files.get(i) != null) {
                System.out.println("i: "+i+"\nFiltype: "+files.get(i).type());
                if(files.get(i).type().equals("image/jpeg") || files.get(i).type().equals("image/png")) {
                    picture = new Picture(project, title+"_bilde_"+(i+1), files.get(i));
                    project.addPicture(picture);
                } else {
                    error += "Fil nummer "+(i+1)+" er av typen "+files.get(i).type()+" og ikke av typen .JPG eller .PNG og ble dermed ikke lagt til. \n";
                }
            } else {
                error = "Ingen filer funnet";
            }
        }
    } else {
        error = "Velg en tittel for bildene";
    }
    if(error.equals("")) {
        flash.success("Picture(s) added");
    } else {
        flash.error(error);
    }
    addPicture(id);
}

Answer 1

如果有人感兴趣的话，可以像这样工作：

public static void uploadPictures(long id, String title, File fake) {
    List<Upload> files = (List<Upload>) request.args.get("__UPLOADS");
    if(files != null) {
        Project project = Project.findById(id);
        Picture picture;
        Blob image;
        InputStream inStream;
        for(Upload file: files) {
            if(file != null) {
                try {
                    inStream = new java.io.FileInputStream(file.asFile());
                    image = new Blob();
                    image.set(inStream, new MimetypesFileTypeMap().getContentType(file.asFile()));
                    picture = new Picture(project, file.getFileName(), image);
                    project.addPicture(picture); // stores the picture
                } catch (FileNotFoundException e) {
                    System.out.println(e.toString());
                }
            }
        }
    }
    addPicture(id); //renders the image upload view
}

如果可能的话，很高兴获得带有Blob对象数组的可行解决方案，而不必要求request.args.get（“ __ UPLOADS”）。