我可以根据其字段的值获取一个枚举吗？

Question

我想根据其字段值获取一个特定的枚举。

枚举：

public enum CrimeCategory {
    ASBO ("Anti Social Behaviour"),
    BURG ("Burglary"),
    CRIMDAM ("Criminal Damage And Arson"),
    DRUGS ("Drugs"),
    OTHTHEFT ("Other Theft"),
    PUPDISOR ("Public Disorder And Weapons"),
    ROBBERY ("Robbery"),
    SHOPLIF ("Shoplifting"),
    VEHICLE ("Vehicle Crime"),
    VIOLENT ("Violent Crime"),
    OTHER ("Other Crime");

    private  String category;


    private CrimeCategory (String category) {
        this.category = category;
    }

    public String returnString() {
        return category; 
    }
}

获取一个新的枚举：

aStringRecivedFromJson = "Anti Social Behaviour"
CrimeCategory crimeCategoryEnum;
crimeCategoryEnum = CrimeCategory.valueOf(aStringRecivedFromJson);

我一直在尝试为上述方法带来一个枚举，以便可以将其HashMap与其他Crime信息一起存储在其中。

预期结果： ASBO

Answer 1

供参考，这是HashMap的替代解决方案：

enum CrimeCategory {
  ASBO("Anti Social Behaviour"),
  BURG("Burglary"),
  CRIMDAM("Criminal Damage And Arson"),
  DRUGS("Drugs"),
  OTHTHEFT("Other Theft"),
  PUPDISOR("Public Disorder And Weapons"),
  ROBBERY("Robbery"),
  SHOPLIF("Shoplifting"),
  VEHICLE("Vehicle Crime"),
  VIOLENT("Violent Crime"),
  OTHER("Other Crime");

  private static final Map<String, CrimeCategory> map = new HashMap<>(values().length, 1);

  static {
    for (CrimeCategory c : values()) map.put(c.category, c);
  }

  private final String category;

  private CrimeCategory(String category) {
    this.category = category;
  }

  public static CrimeCategory of(String name) {
    CrimeCategory result = map.get(name);
    if (result == null) {
      throw new IllegalArgumentException("Invalid category name: " + name);
    }
    return result;
  }
}