Android，我可以将AsyncTask放在单独的类中并进行回调吗？

Question

我只是在学习AsyncTask，并希望将其用作单独的类，而不是子类。

例如，

class inetloader extends AsyncTask<String, Void, String> {


    @Override
    protected String doInBackground(String... urls) {

        String response = "";

            DefaultHttpClient client = new DefaultHttpClient();
            HttpGet httpGet = new HttpGet(urls[0]);
            try {
                HttpResponse execute = client.execute(httpGet);
                InputStream content = execute.getEntity().getContent();

                BufferedReader buffer = new BufferedReader(
                        new InputStreamReader(content));
                String s = "";
                while ((s = buffer.readLine()) != null) {
                    response += s;
                }

            } catch (Exception e) {
                e.printStackTrace();
            }

        return response;
    }


    @Override
    protected void onPostExecute(String result) {
        Log.e("xx",result);
        // how do I pass this result back to the thread, that created me?
    }


}

和main（ui）线程：

inetloader il = new inetloader();
il.execute("http://www.google.com");
//il.onResult()
//{
    ///do something...
//}

谢谢！

Answer 1

使用界面。就像是：

interface CallBackListener{
  public void callback();
}

然后在您的UI线程中执行此操作：

inetloader il = new inetloader();
li.setListener(this);
il.execute("http://www.google.com");

在inetloader中，添加：

   CallBackListener mListener;

   public void setListener(CallBackListener listener){
     mListener = listener;
   }

然后在postExecute（）中，执行以下操作：

   mListener.callback();